我想知道执行以下代码的最佳方法是什么:
select Id,Id2 from someTable
where Id in (select someId from someTable2)
or Id2 in (select someId from someTable2)
我检查了执行计划,我可以看到someTable2的两个表扫描(没有索引)。
我正在寻找的解决方案与索引无关,而是与构建此查询的更好方法有关。
提前致谢。
答案 0 :(得分:2)
SELECT id
, id2
FROM sometable
WHERE EXISTS (
SELECT someid
FROM sometable2
WHERE someid IN (sometable.id, sometable.id2)
)
答案 1 :(得分:1)
使用JOIN
,
SELECT DISTINCT a.ID, a.ID2
FROM someTable a
INNER JOIN someTable2 b
ON b.someID IN (a.id, a.id2)
<强>更新强>
SELECT ID, ID2
FROM someTable a INNER JOIN someTable2 b ON b.someID = a.id
UNION
SELECT ID, ID2
FROM someTable a INNER JOIN someTable2 b ON b.someID = a.id2
答案 2 :(得分:1)
除非someid
上有索引,否则任何查询都必须进行完整的表扫描。您可以尝试更改为加入:
SELECT DISTINCT T1.Id,T1.Id2
FROM someTable T1
LEFT JOIN someTable2 T2 ON T1.Id = T2.someId
LEFT JOIN someTable2 T3 ON T1.Id = T3.someId
WHERE T2.someId IS NOT NULL
OR T3.someId IS NOT NULL