-(BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
[self.map removeAnnotations:self.map.annotations];
if ([textField isEqual:self.searchText]) {
NSPredicate *bPredicate =
[NSPredicate predicateWithFormat:@"name contains[c], %@",self.searchText.text];
self.filteredArray = [self.hotelArray filteredArrayUsingPredicate:bPredicate];
NSLog(@" HEARE %@",self.filteredArray);
[self markAllHotels];
}
return YES;
}
hotelArray
和filteredArray
是NSArray
s。
hotelArray
包含hotel
类型的对象,其中hotel
具有属性name
。
问题:
我希望在hotelArray
与hotel.name
[文本字段]中输入的文字相匹配时根据hotel.name
过滤searchText
,但我得到一个空的self.filteredArray
。
答案 0 :(得分:71)
尝试以下行,并确保properyName
区分大小写。并且您已将,
置于谓词格式中,这就是为什么它不起作用。只需用以下代码替换您的代码。
目标C
NSPredicate *bPredicate = [NSPredicate predicateWithFormat:@"SELF.name contains[cd] %@",self.searchText.text];
self.filteredArray = [self.hotelArray filteredArrayUsingPredicate:bPredicate];
NSLog(@"HERE %@",self.filteredArray);
<强>夫特强>
var bPredicate: NSPredicate = NSPredicate(format: "SELF.name contains[cd] %@", self.searchText.text)
self.filteredArray = self.hotelArray.filteredArrayUsingPredicate(bPredicate)
NSLog("HERE %@", self.filteredArray)
使用swift filter
var searchText = "Galaxy"
let filteredArray = hotelArray.filter { $0["name"] == searchText }
print("** Result ** \n\(filteredArray)")
Swift 3.0
let arrEmp = [["name": "James", "age" : 27, "city" : "New york"],
["name": "Johnson", "age" : 24, "city" : "London"],
["name": "Alex", "age" : 28, "city" : "Newark"],
["name": "Mark", "age" : 25, "city" : "Paris"],
["name": "Steve", "age" : 25, "city" : "Silicon Valley"],
["name": "Lary", "age" : 28, "city" : "New york"]]
// *** Filter by Name exact match ***
var filterByName = arrEmp.filter { $0["name"] == "Mark" }
print("filterByName \(filterByName)")
// *** Filter by Age ***
var filterByAge = arrEmp.filter { $0["age"] as! Int > 25 }
print("filterByAge \(filterByAge)")
Swift 4.0
var filterByName = arrEmp.filter
do {
$0["name"] == "Mark"
}
print("filterByName filterByName)")
var filterByAge = arrEmp.filter
do {
$0["age"] as! Int > 25
}
print("filterByAge filterByAge)")
答案 1 :(得分:5)
根据您的信息,这是您的情况:
self.hotelArray // Array in which we perform a search
self.filteredArray // Result array
name // Property of the object used for the predicate
这个谓词适合你:
NSString *searchText = self.searchText.text;
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"self.name contains[c] %@", searchText];
self.filteredArray = [self.hotelArray filteredArrayUsingPredicate:predicate];
答案 2 :(得分:1)
这是可能适合您的谓词方法。
-(void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope
{
[filteredContactArray removeAllObjects];
NSArray *tempArray = [hotelArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"name contains[c] %@ OR name contains[cd] %@",searchText]];
filteredArray = [NSMutableArray arrayWithArray:tempArray];//if you want the filtered array to be mutable or tempArray will work as as desired by you.
}
包含[c] - 表示区分大小写的谓词。 包含[cd] - 不区分大小写的字符串
答案 3 :(得分:1)
查看此库
https://github.com/BadChoice/Collection
它有许多简单的数组函数,永远不会再写一个循环
所以你可以这样做:
NSArray* hotels = [self.hotelArray filter:^BOOL(Hotel *hotel) {
[return hotel.name isEqualToString:searchText];
}];
或只是
NSArray* hotels = [self.hotelArray where:@"name" is:searchText];
:)
答案 4 :(得分:0)
我不确定这是不是你想做的事情:
-(NSArray*)searchString:(NSString*)stringToSearch inArray:(NSArray*)myArray
{
NSMutableArray* filtredArray = [[NSMutableArray alloc] init];
for (NSString* elmnt in myArray)
{
if ([elmnt rangeOfString:stringToSearch].location != NSNotFound) [fitredArray addObject:elmnt];
}
return filtredArray;
}