Question

我有我的代码，但在解决方案3中，我希望将分钟的时间转换为小时和分钟（即341分钟到5小时41分钟）。

  public class CityToSurf
  {
        //Method for lowest time index
        private int getMinIndex(int[] times){
        int minValue = times[0]; 
        int minIndex = 0;//default value to start with
        for(int counter=0;counter<times.length;counter++){  
            if(times[counter] < minValue){ 
              minIndex = counter;
              minValue = times[counter]; 
            }  
           }   
           return minIndex; 
        }
        public static void main (String[] arguments){

        CityToSurf cs = new CityToSurf();

        //create array of times and names
        int[] times ={341,273,278,329,445,402,388,275,243,334,412,393,299,343,317,265};
        String[] names ={"Elana","Thomas","Hamilton", "Suzie", "Phil","Matt", "Alex", "Emma", "John","James" ,"Jane", "Emily", "Daniel" ,"Neda", "Aaron", "Kate"};

        //Solution 1      
        int fastestRunnerIndex =  cs.getMinIndex(times);
        System.out.println("Solution 1:");
        System.out.println(names[fastestRunnerIndex]+ "  "+ times[fastestRunnerIndex] );

        //Solution 2
        System.out.println("Solution 2:");
        cs.getSortedArray(times, names);

      //Solution 3
        System.out.println("Solution 3:");
        cs.timeConvert(times, names);


    }

    private void getSortedArray(int[] times, String[] names){

         //store in a local variable the unchanged/old list
         int[] oldTimes = new  int[times.length];

         for (int i=0;i<times.length;i++){
              oldTimes[i] = times[i];

         }

         java.util.Arrays.sort(times);//sort the times from min to max times for the PLACEMENT

         int place =1; //this is to initialize the placement for a list from 1 to 16.

        //loop over my old times list and match the time in the old times with sorted times to find the corresponding index that will be used to get name and time
         for (int i=0;i<times.length;i++){
             //SORTED the min to max time from the list 
             int newSortedTime= times[i];


             //loop over the sorted times to match the time
             int oldIndex =0;
             for (int j=0; j<oldTimes.length;j++){
                 int oldUnsortedTime = oldTimes[j];

                 if (oldUnsortedTime == newSortedTime){
                     oldIndex = j;
                     System.out.println(place + "  " +names[oldIndex] + "   "  + oldTimes[oldIndex] );
                     place++;//increment to next placement
                 }

             }  }

         }

    private void timeConvert(int[] times, String[] names){
        int[] oldTimes = new  int[times.length];
        int hours = times / 60; //since both are ints, you get an int
        int minutes = times % 60;
        System.out.printf("%d:%02d", hours, minutes);
             }



    }

Answer 1

次不是int它是int []因此这不起作用。我认为你正在寻找类似的东西：

  private void timeConvert(int[] times, String[] names) {
    for (int time : times) {
      int hours = time / 60; //since both are ints, you get an int
      int minutes = time % 60;
      System.out.printf("%d:%02d\n", hours, minutes);
    }
  }

Answer 2

它应该是这样的：

private void timeConvert（int [] times，String [] names）{

int length = times.length ;
    for(int i = 0;i<length;i++){
         int hours = times[i] / 60;           
         int minutes = times[i] % 60;
         System.out.printf("%d:%02d", hours, minutes);
    }
}

我想在小时和分钟（00:00）输出我的代码中的时间并需要帮助。这就是我到目前为止所拥有的

2 个答案: