Question

我怎样才能得到这个：

(
[0] => Array
    (
        [name] => variation
        [value] => variation1
    )

[1] => Array
    (
        [name] => variationid
        [value] => 70105
    )

[2] => Array
    (
        [name] => fullName
        [value] => 
    )

[3] => Array
    (
        [name] => address
        [value] => 
    )

[4] => Array
    (
        [name] => country
        [value] => usa
    )

[5] => Array
    (
        [name] => state
        [value] => Utah
    )

看起来像这样：

$fields['variation']=>variation1[variationid]=>70105.. etc

我试过了：

foreach($_POST['fields'] as $key => $value){
    $fields[$key] = $value;
}

我认为这应该可行，但它会让我看起来完全一样。这只是从jquery传递到POST的serializedArray（）;我基本上只是希望能够使用$ fields ['variation']访问来访问它。但它让它变得困难。

Answer 1

您没有正确使用嵌套数组，$value使用name和value保存数组，因为$key（0,1，...）是不需要，你甚至不需要定义它。

foreach ($_POST['fields'] as $data) {
    $fields[ $data['name'] ] = $data['value'];
}

php嵌套数组到字典

1 个答案: