Question

我很困惑，因为有很多程序。但我看起来像这样。我会输入一个像“a4 c3 h3 a2”等旋律然后我想听到这个。有人知道我在找什么吗？提前谢谢

Answer 1

从音符名称计算频率很容易。每个半音符距前一音符2 ^（1/12），440 Hz为A4。

如果你有机会在Windows上，你可以尝试这段代码，通过PC扬声器播放一首歌：

import math
import winsound
import time

labels = ['a','a#','b','c','c#','d','d#','e','f','f#','g','g#']
# name is the complete name of a note (label + octave). the parameter
# n is the number of half-tone from A4 (e.g. D#1 is -42, A3 is -12, A5 is 12)
name   = lambda n: labels[n%len(labels)] + str(int((n+(9+4*12))/12))
# the frequency of a note. the parameter n is the number of half-tones
# from a4, which has a frequency of 440Hz, and is our reference note.
freq   = lambda n: int(440*(math.pow(2,1/12)**n))

# a dictionnary associating note frequencies to note names
notes  = {name(n): freq(n) for n in range(-42,60)}

# the period expressed in second, computed from a tempo in bpm
period = lambda tempo: 1/(tempo/60)

# play each note in sequence through the PC speaker at the given tempo
def play(song, tempo):
    for note in song.lower().split():
        if note in notes.keys():
            winsound.Beep(notes[note], int(period(tempo)*1000))
        else:
            time.sleep(period(tempo))

# "au clair de la lune"!! 'r' is a rest
play( 'c4 c4 C4 d4 e4 r d4 r c4 e4 d4 d4 c4 r r r '
      'c4 C4 c4 d4 e4 r d4 r c4 e4 d4 d4 c4 r r r '
      'd4 d4 d4 d4 A3 r a3 r d4 c4 B3 a3 g3 r r r '
      'c4 c4 c4 d4 e4 r d4 r c4 e4 d4 d4 c4 r r r ', 180 )

（请注意我使用的是python 3.x，您可能需要调整代码的某些部分才能在python 2.x上使用它。）

顺便说一句，我使用abcdefg作为比例，但您肯定会找到使用h代替b的方法。

Answer 2

一个外部选项JFugue为shown here（使用Groovy）。请注意，您将使用Jython而不是Python，这有望作为答案在范围内。

Answer 3

你可以使用任何产生MIDI输出的库，如果是.net我建议来自微软的Stephen Toub创建的那个（找不到我从哪里得到它，但google就可以找到它。）

Answer 4

检查一下：http://www.algorithm.co.il/blogs/index.php/pytuner/ 这是一个非常相似的项目，看起来是一个非常不错的参考。

Answer 5

这是与@Adrien Plisson 相同的程序，但适用于 macOS：

import math
import time
import pygame
import numpy

sampleRate = 44100
freq = 440

labels = ['a','a#','b','c','c#','d','d#','e','f','f#','g','g#']

name   = lambda n: labels[n%len(labels)] + str(int((n+(9+4*12))/12))
# name is the complete name of a note (label + octave).
# the parameter n is the number of half-tone from A4 (e.g. D#1 is -42, A3 is -12, A5 is 12)

freq   = lambda n: int(440*(math.pow(2,1/12)**n))
# the frequency of a note.
# the parameter n is the number of half-tones from a4, which has a frequency of 440Hz, and is our reference note.

notes  = {name(n): freq(n) for n in range(-42,60)}
# a dictionnary associating note frequencies to note names

period = lambda tempo: 1/(tempo/60)
# the period expressed in second, computed from a tempo in bpm

def play(song, tempo):
    for note in song.lower().split():
        if note in notes.keys():
            pygame.mixer.init(notes[note])
            arr = numpy.array([4096 * numpy.sin(2.0 * numpy.pi * notes[note] * x / sampleRate) for x in range(0, sampleRate)]).astype(numpy.int16)
            arr2 = numpy.c_[arr,arr]
            sound = pygame.sndarray.make_sound(arr2)
            sound.play(-1)
            pygame.time.delay(1000)
            sound.stop()
        else:
            time.sleep(period(tempo))
# play each note in sequence through the PC speaker at the given tempo

play( 'c4 c4 C4 d4 e4 r d4 r c4 e4 d4 d4 c4 r r r '
      'c4 C4 c4 d4 e4 r d4 r c4 e4 d4 d4 c4 r r r '
      'd4 d4 d4 d4 A3 r a3 r d4 c4 B3 a3 g3 r r r '
      'c4 c4 c4 d4 e4 r d4 r c4 e4 d4 d4 c4 r r r ', 180 )
# "au clair de la lune"!! 'r' is a rest

我怎样才能创作出旋律？有声音模块吗？

5 个答案: