Vb.net随机数生成器重复相同的数字

时间:2013-10-29 21:40:04

标签: vb.net random

我应该在随机数生成器编码中添加什么,所以数字不能连续多次重复?

我的随机数生成器如下所示:

Dim rn As New Random
TextBox1.Text = rn.Next(1, 4)
If TextBox1.Text = 1 Then
    Form4.Show()
    Form4.Timer1.Start()
End If

If TextBox1.Text = 2 Then
    Form7.Show()
    Form7.Timer1.Start()
End If

If TextBox1.Text = 3 Then
   Form8.Show()
   Form8.Timer1.Start()
End If

4 个答案:

答案 0 :(得分:1)

给定N(目前N = 3,但它可能是其他东西,如你所说),尝试构造1,...,N的随机排列,然后按生成的顺序打开文本框。请注意,这意味着您一次生成N个数字并全部使用它们,然后再生成N个。搜索“随机排列”以找到算法。

答案 1 :(得分:1)

将Random实例“rn”移出到Class(Form)级别,这样它只会为Form创建ONCE,并且反复使用同一个实例:

Public Class Form1

    Private rn As New Random

    Private Sub SomeMethod()
        TextBox1.Text = rn.Next(1, 4)
        If TextBox1.Text = 1 Then
            Form4.Show()
            Form4.Timer1.Start()
        End If

        If TextBox1.Text = 2 Then
            Form7.Show()
            Form7.Timer1.Start()
        End If

        If TextBox1.Text = 3 Then
            Form8.Show()
            Form8.Timer1.Start()
        End If
    End Sub

End Class

答案 2 :(得分:0)

要获得1到N(含)之间的随机整数值,您可以使用以下内容。

CInt(Math.Ceiling(Rnd() * n))

答案 3 :(得分:0)

如果您希望每个号码仅使用一次,则需要执行以下操作:

Const FirstNumber As Integer = 1
Const LastNumber As Integer = 5

' Fill the list with numbers
Dim numberList as New List(Of Integer)
For i As Integer = FirstNumber To LastNumber Step 1
    numberList.Add(i)
Next i

Dim rand as New Random()
While numberList.Count > 0
    ' draw a random number from the list
    Dim randomIndex As Integer = rand.Next(0, numberList.Count - 1)
    Dim randomNumber As Integer = numberList(randomIndex)

    ' Do stuff with the number here        
    TextBox1.Text = randomNumber

    ' remove the number from the list so it can't be used again
    numberList.RemoveAt(randomIndex)
End While