Question

我无法访问以下数组的内部值。

对象1访问 *我使用的第一个对象中的值* 值我使用了以下方法：

{{$info[0]->title}} 
{{$info[0]->about}}

我正在尝试访问内部阵列中的价值 ......我该怎么办？

 [

{*"pageID":1,"userID":2,"title":"CrossFit Invictus","logo":"","about":"Invictus is a 5,000 sq\/ft. fitness coaching facility equipped with men\u2019s and women\u2019s locker rooms and a designated kid\u2019s area, located in Little Italy\/Downtown San Diego, California. We offer group, semi-private and individual coaching. Our workouts are comprised of constantly varied functional movements (like pushing, pulling, squatting, lifting, running) in a manner designed to help you achieve your fitness goals.","links":"Street\r\nCar park","createdDate":"2013-10-28 14:14:40","status":1*},


    [

    {"postID":1,"author":1,"pageID":1,"type":"2","post_date":"2013-10-28 00:00:00","visibility":0,"content":"**Now I been datin this girl named Katie, she hot as hell\r\nAnd her body crazy, body shaven and it dont smell\r\nAnd I don't fall for chickens\r\nBut this one a little different\r\nBody sickening\r\nPlus she really good at making breaded chicken**","image":"EHJTRHTJ","youtube_url":"FFEFEFEWFED","is_profile":0,"likes":0,"comments":0,"post_status":1},
    {"postID":2,"author":5,"pageID":1,"type":"1","post_date":"2013-10-27 10:21:15","visibility":0,"content":"posts about empires","image":"dfsfsf","youtube_url":"efefefef","is_profile":0,"likes":0,"comments":0,"post_status":1},{"postID":6,"author":12,"pageID":1,"type":"1","post_date":"2013-10-27 00:00:00","visibility":0,"content":"post about emperors ","image":"fhfghfh","youtube_url":"hththt","is_profile":1,"likes":0,"comments":0,"post_status":1}

      ],

      [
    {"id":1,"person":1,"page":1,"reason":"blab blab blab blab blabber","positive":1, "time_posted": "**2013-10-28 15:14:43**"}
      ]


    ]

用于传递数据的查询：

//Retrieve  BASIC PAGE INFO
        $page       = DB::table('pages')->where('pageID', $id)->first();
        $page_posts =  DB::table('pagesposts')->where('pageID', $id)->get();
        $page_likes =  DB::table('pagelikes')->where('page', $id)->get();

  //Page data 
        $info = array ($page, $page_posts, $page_likes) ;



        return View::make('testingview', compact('info'));

Answer 1

您应该像这样传递数据：

//Page data 
        $info = array();
        $info['page'] = $page;
        $info['page_posts'] = $page_posts;
        $info['page_likes'] = $page_likes; 

return View::make('testingview', $info);

然后在您的视图中，您可以像单独的变量一样访问它：

$page, $page_posts and $page_likes

例如：

{{ $page->title }}

您应该注意，调用compact()函数会创建一个包含变量及其值的数组，这很可能是您问题的根源。

如何在laravel视图中访问嵌套数组？ Laravel 4

1 个答案: