SQL合并单元格

Question

我有这张桌子： T：

d

我要做的是在一个单元格（合并单元格）中获取每个s_id所有符号（DBSymbol）。

我找到了this教程，这是我的代码：

select T.s_id, 
    (select '; ' + D.symbol 
     from D 
     where T.D_b_id = D.id 
     FOR XML PATH('')) [DBSymbol]
from T 

但这是我得到的：

有什么问题？

Answer 1

select DISTINCT T.s_id, 
Stuff((SELECT DISTINCT  '; ' + D.symbol 
     from  D 
     --where T.D_b_id = D.id 
     FOR XML PATH('')),1,1,'') [DBSymbol]
from T

示例here

Answer 2

试试这个 -

SELECT t1.s_id,
       STUFF(
           (SELECT '; ' + symbol AS [text()]
               FROM   (
                      SELECT t.s_id,
                             d.symbol
                      FROM   T
                      INNER JOIN D ON  T.d_b_id = D.id
                      WHERE t.s_id = t1.s_id                      
                      ) x
            FOR XML PATH('')
           ), 1, 1, '')
FROM T t1
GROUP BY t1.s_id

检查：SQL Fiddle