ajaxCRUD:关于插入的两个问题

时间:2013-10-29 13:40:01

标签: php jquery mysql ajax


我开始玩ajaxCRUD,这似乎是简单而有效的课程 我有一个像这样的用户表:

CREATE TABLE tbl_users (
  usr_id        INT NOT NULL AUTO_INCREMENT ,
  usr_name      VARCHAR( 64 ) NOT NULL DEFAULT '' ,
  usr_surname   VARCHAR( 64 ) NOT NULL DEFAULT '' ,
  usr_pwd       VARCHAR( 64 ) NOT NULL ,
  usr_level     INT( 1 ) NOT NULL DEFAULT 0,
  PRIMARY KEY ( usr_id )
) ENGINE = InnoDB;

我的PHP代码是:

<?php
  $tblUsers->omitPrimaryKey();

  $tblUsers->displayAs("usr_name", "Nome");
  $tblUsers->displayAs("usr_surname", "Cognome");
  $tblUsers->displayAs("usr_pwd", "Password");
  $tblUsers->displayAs("usr_level", "Livello");
  $tblUsers->omitField("usr_pwd");

  $tblUsers->modifyFieldWithClass("usr_pwd", "password");

  $allowable_vals = array(1 => "USER", 2 => "ADMIN", 3 => "SUPERUSER");

  $tblUsers->defineAllowableValues("usr_level", $allowable_vals);
  $tblUsers->formatFieldWithFunction('usr_level', 'make_usr_level');
  $tblUsers->onAddExecuteCallBackFunction("AddCallBack");

  $tblUsers->addButtonToRow("Dettagli", "UserDetails.php");
  $tblUsers->addButtonToRow("Collega case", "HousesList.php"); 

  $tblUsers->setLimit(30);

  #my self-defined functions used for formatFieldWithFunction
  function make_usr_level($val){
    return FAUser::LevelToString($val);
  }  

  function AddCallBack($array)
  { 
    //these indexes are the fields of the db
    $success = qr("INSERT INTO tbl_users 
                    ( usr_id, 
                      usr_name, 
                      usr_surname, 
                      usr_pwd, 
                      usr_level )
                   VALUES (NULL, 
                           '" . $array[usr_name] . "', 
                           '" . $array[usr_surname] . "', 
                           AES_ENCRYPT('" . $array[usr_pwd] . "', 
                                       SHA2('FonteAlma_2013', 512)), 
                           " . $array[usr_level] . ");");
  }

  #actually show to the table
  $tblUsers->showTable();

?>  

表格显示正确并显示已插入的用户,但是当我添加新用户时,我得到:

4 - TheGivenName - TheGivenSurname - [BLOB - 7 B] - 0

因此密码和用户级别设置不正确。

另外,当我将水平字段编辑到表格中时,这是一个包含三个级别的组合框,无论我选择什么值,我总是得到0。

哪里错了?

问候。

1 个答案:

答案 0 :(得分:0)

我编写了我的解决方案。

也许这不是最佳/正确的解决方案......但似乎有效。

我在执行ADD查询之前添加了一个方法onBeforeAddExecuteCallBackFunction()。 如果此回调返回FALSE,则执行结束(函数doAction返回)。否则继续。

这是差异文件:

263d262
<   var $onBeforeAddExecuteCallBackFunction;
352d350
<     $this->onBeforeAddExecuteCallBackFunction   = '';
653,657d650
<   function onBeforeAddExecuteCallBackFunction($function_name){
<     $this->onBeforeAddExecuteCallBackFunction = $function_name;
<     $this->ajax_add = false;
<   }
< 
900,906d892
<         // Added
<         if ($this->onBeforeAddExecuteCallBackFunction != '') {
<           // If the Callback return FALSE, I quit
<           if (!call_user_func($this->onBeforeAddExecuteCallBackFunction, $submitted_array))
<           return;
<         }
<