在vb.net中解析Json

时间:2013-10-28 18:25:56

标签: json vb.net

我有以下Json,我希望在vb.net中循环并提取问题和结果。我试图使用Newtonsoft.json,但我收到错误,虽然JSONlint验证了Json。实现这一目标的正确方法是什么?

{
    "Vehicle_Check": [
        19,
        {
            "question": "Brakes",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Water Levels",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Horn",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Washers",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Wipers",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Indicators",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Reflectors",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Oil Levels",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Lights",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Mirrors",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Steering",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Tyres Wheels",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Battery",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Fuel or Oil Leaks",
            "result": "OK",
            "Fault": ""
        },
        {
            "question": "Other",
            "result": "OK",
            "Fault": ""
        }
    ]
}

我用来解析Json的代码是:

Dim o As JObject = JObject.Parse(VCItem.Check)
Dim results As List(Of JToken) = o.Children().ToList
For Each item As JProperty In results
    item.CreateReader()
    Select Case item.Name
        'process data here
    End Select
Next

这仅返回最后一个元素:

{[
    19,
    {
        "question": "Other",
        "result": "OK",
        "Fault": ""
    }
]}

1 个答案:

答案 0 :(得分:0)

实际上它正在返回第一个和最后一个元素。鉴于您发布的内容,19是数组中的第一个项目,无论如何都不合适。

尝试这个(是的,我知道它看起来很可怕)但我不得不从列表中删除19,因为它不是一个对象而是一个字符串。你的数组中有不同的类型,如果必须保留,你需要测试字符串。我正在研究一种更好的方式来自己阅读JSON,但这比我希望的时间更长。

    Dim o As JObject = JObject.Parse(VCItem)
    Dim results As List(Of JToken) = o.Children().ToList
    For Each item As JProperty In results
        item.CreateReader()
        If item.Value.Type = JTokenType.Array Then
            Dim results2 As List(Of JToken) = item.Value.ToList
            For Each subitem As JObject In results2
                Dim results3 As List(Of JToken) = subitem.Children().ToList
                For Each temp2 As JProperty In results3
                    temp2.CreateReader()
                    MsgBox(temp2.Name)
                    MsgBox(temp2.Value)
                Next
            Next
        End If
    Next

找到一种更简单的方法来显示你的值,但仍然取决于JSON字符串的结构(在这里找到更简单的方法:How to Parse Json children in VB.NET Newtonsoft

    Dim o As JObject = JObject.Parse(VCItem)
    Dim results As List(Of JToken) = o.Children().ToList
    For Each item As JProperty In results
        item.CreateReader()
        If item.Value.Type = JTokenType.Array Then
            For Each subitem As JObject In item.Values
                MsgBox(subitem("question"))
                MsgBox(subitem("result"))
                MsgBox(subitem("Fault"))
            Next
        End If
    Next