我有一个包含表“person”,“company”,“shop”等的数据库。这些表中的许多表必须具有“联系信息”。在Database design - Similar Contact Information for multiple entities中询问了设计此问题的可能性 现在,在我的数据库中,我可以为每个联系人数据提供多个地址,多个电话和多封电子邮件。这是我的数据库架构:
所以,我将中间表“联系”作为将“联系信息”链接到每个表格的最简单方法。
我的问题:这样做是不错的做法,并且只有一行表?
答案 0 :(得分:7)
这就是我设计数据库的方式:
address_types
id unsigned int(P)
description varchar(10) // Mailing, Physical, etc.
addresses
id unsigned int(P)
line1 varchar(50) // 123 Main Street, etc.
line2 varchar(50) // Default NULL
city_id unsigned int(F cities.id)
zip varchar(6) // 12345, A1A 1A1, etc.
zip4 char(4) // Default NULL
lat decimal(10,8) // 13.12345678, etc.
lon decimal(11,8) // 110.12345678, etc.
cities
id unsigned int(P)
state_id unsigned int(F states.id)
name varchar(50) // Omaha, Detroit, Tampa, etc.
companies
id unsigned int(P)
name varchar(75) // IBM, Microsoft, RedHat, etc.
...
companies_addresses
id unsigned int(P)
company_id unsigned int(F companies.id)
address_id unsigned int(F addresses.id)
address_type_id unsigned int(F address_types.id)
companies_contacts
id unsigned int(P)
company_id unsigned int(F companies.id)
contact_id unsigned int(F contacts.id)
contact_type_id unsigned int(F contact_types.id)
companies_emails
id unsigned int(P)
company_id unsigned int(F companies.id)
email_id unsigned int(F emails.id)
email_type_id unsigned int(F email_types.id)
contact_types
id unsigned int(P)
description varchar(10) // Home phone, Mobile phone, FAX, etc.
在北美,电话号码如下:CC-AAA-EEE-SSSS-XXXXXXX,其中CC是国家代码,AAA是区号,EEE是交换机,SSSS是电台,XXXXX是电话号码。< / p>
contacts
id unsigned int(P)
country_code varchar(3)
area_code varchar(3)
exchange varchar(3)
station varchar(4)
extension varchar(10) // Default NULL
请参阅ISO 3166-1。
countries
id char(2) // ca, mx, us, etc.
iso3 char(3) // can, mex, usa, etc.
iso_num char(3)
name varchar(44) // Canada, Mexico, United States, etc.
email_types
id unsigned int(P)
description varchar(10) // Personal, Work, etc.
emails
id unsigned int(P)
address varchar(255) // support@ibm.com, etc.
shops
id unsigned int(P)
name varchar(45) // Shop A, Shop B, etc.
...
shops_addresses
id unsigned int(P)
shop_id unsigned int(F shops.id)
address_id unsigned int(F addresses.id)
address_type_id unsigned int(F address_types.id)
shops_contacts
id unsigned int(P)
shop_id unsigned int(F shops.id)
contact_id unsigned int(F contacts.id)
contact_type_id unsigned int(F contact_types.id)
shops_emails
id unsigned int(P)
shop_id unsigned int(F shops.id)
email_id unsigned int(F emails.id)
email_type_id unsigned int(F email_types.id)
请参阅ISO 3166-2。
states
id unsigned int(P)
country_id char(2)(F countries.id)
code varchar(2) // AL, NF, NL, etc.
name varchar(50) // Alabama, Newfoundland, Nuevo León, etc.
答案 1 :(得分:3)
我的问题:这样做是一个好习惯,并且只有一行表吗?
不是真的。看看你的图表,我不得不问:联系人真的可以链接到任意数量的人吗?如果没有,您应该使用'person'作为父表,并使其他表链接到它。
答案 2 :(得分:2)
Personaly,我不喜欢这种方法,因为我们需要为每个表和很多关联表创建任何实体。我建议一个用于联系信息的表和另一个用于地址的表。
informations
- id INT
- name VARCHAR
- value VARCHAR
- type ENUM(phone, email, url, custom)
- idcompany INT NULL
- idcontact INT NULL
和
addresses
- id
- address1
- address2
- district
- postcode
- idcity
- idcompany
- idcontact