Question

我正在寻找在Symfony 2.3上集成CAS身份验证的捆绑包。我找到了这些选项，事实是我不相信，因为几乎所有的捆绑包似乎都被抛弃而没有更新。

1.- sensiolabs / CasBundle：https://github.com/sensiolabs/CasBundle 文档稀疏且不完整。我还没有找到任何使用它的例子。

2.- BeSimple / BeSimpleSsoAuthBundle：https://github.com/BeSimple/BeSimpleSsoAuthBundle 有了这个，我正在测试，我遇到了一些问题。我想我已经解决了第四个问题而且我落后了另一个问题。

3.- Symfony CAS客户端：https://wiki.jasig.org/display/CASC/Symfony+CAS+Client 完全过时了

真的，在symfony中使用CAS进行身份验证的选项很少吗？

Answer 1

之前我有同样的问题，我使用BeSimpleSsoAuthBundle解决了它，但你必须做一些改变：假设您的UserBundle已经实现了您的用户实体，并且必须覆盖一个唯一属性sgid： 1- BeSimple \ SsoAuthBundle \ Security \ Core \ User：

<?php

namespace Application\UserBundle\Security\BeSimple\SpawnedUserProvider;

use BeSimple\SsoAuthBundle\Security\Core\User\SpawnedUserProvider;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\User;
use Symfony\Component\HttpFoundation\RedirectResponse;


class SsoUserProvider extends SpawnedUserProvider
{
/**
 * @var array
 */
private $roles;

/**
 * Constructor.
 *
 * @param array $roles An array of roles
 */
private $entityManager;
private $securityContext;

public function __construct($em, $securityContext) {
    $this->em = $em; 
    $this->securityContext = $securityContext; 
}

/**
 * {@inheritdoc}
 */
public function loadUserByUsername($username)
{
    $session = $this->securityContext;

    $qb = $this->em->createQueryBuilder();
    $qb->select("u")
        ->from('ApplicationUserBundle:User', 'u')
        ->where('u.sgid = :sgid')
        ->AndWhere('u.status = 1')
        ->setParameter("sgid", $username);

   $result = $qb->getQuery()->getOneOrNullResult();

    if ($result == NULL) {
        $session->getFlashBag()->add('error', 'Vous ne pouvez pas vous connecter car votre compte est désactivé');
        return new RedirectResponse('login');
    }

   $user_name = $result->getFirstName().' '.$result->getLastName();
    $session->set('userId', $result->getId());
   if ($result->getUserType() == 1) {
       $this->roles = array('ROLE_ADMIN');
   }else if ($result->getUserType() == 0){
       $this->roles = array('ROLE_USER');
   }else{
        $session->getFlashBag()->add('error', 'Vous ne pouvez pas vous connecter car votre compte n\'a pas de rôle');
        return new RedirectResponse('logout');
   }
    return $this->spawnUser($user_name);
}

/**
 * {@inheritDoc}
 */
public function refreshUser(UserInterface $user)
{
    if (!$user instanceof User) {
        throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.', get_class($user)));
    }

    return $this->spawnUser($user->getUsername());
}

/**
 * {@inheritDoc}
 */
public function supportsClass($class)
{
    return $class === 'Symfony\Component\Security\Core\User\User';
}

/**
 * Spawns a new user with given username.
 *
 * @param string $username
 *
 * @return \Symfony\Component\Security\Core\User\User
 */
private function spawnUser($username)
{
    //$this->roles = $this->userType;
    return new User($username, null, (array)$this->roles, true, true, true, true);
  }
}

2-覆盖BeSimple \ SsoAuthBundle \ Security \ Core \ Authentication \ Provider：

<?php

namespace Application\UserBundle\Security\BeSimple\Authentication\Provider;

use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\Exception\UsernameNotFoundException;
use Symfony\Component\Security\Core\Exception\BadCredentialsException;
use BeSimple\SsoAuthBundle\Security\Core\User\UserFactoryInterface;

/*
 * @Override 
 */
use    BeSimple\SsoAuthBundle\Security\Core\Authentication\Provider\SsoAuthenticationPr ovider;

class AppAuthenticationProvider extends SsoAuthenticationProvider
{
/**
 * @var UserProviderInterface
 */
private $userProvider;

/**
 * @var bool
 */
private $createUsers;

/**
 * @var bool
 */
private $hideUserNotFound;

/**
 * @Override file
 * @throws \Symfony\Component\Security\Core\Exception\UsernameNotFoundException
 * @throws \Symfony\Component\Security\Core\Exception\BadCredentialsException
 *
 * @param string $username
 * @param array $attributes
 *
 * @return UserInterface
 */
protected function provideUser($username, array $attributes = array())
{
    try {
        $user = $this->retrieveUser($username);
    } catch (UsernameNotFoundException $notFound) {
        if ($this->createUsers && $this->userProvider instanceof UserFactoryInterface) {
            $user = $this->createUser($username, $attributes);
        } elseif ($this->hideUserNotFound) {
            throw new BadCredentialsException('Bad credentials', 0, $notFound);
        } else {
            throw $notFound;
        }
    }

    return $user;
  }

}

3-当用户登录您的应用程序时，在会话中保存所需信息：

<?php

namespace Application\UserBundle\Security\Authentication\Handler;

use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\Routing\Router;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\Security\Http\Authentication\AuthenticationSuccessHandlerInterface;
use Doctrine\ORM\EntityManager;

class LoginSuccessHandler implements AuthenticationSuccessHandlerInterface
{
protected 
    $router,
    $security,
    $entityManager;

public function __construct(Router $router, SecurityContext $security, EntityManager $entityManager)
{
    $this->router = $router;
    $this->security = $security;
    $this->entityManager = $entityManager;
}

public function onAuthenticationSuccess(Request $request, TokenInterface $token)
{
    $session = $request->getSession();

    $attributes = $this->security->getToken()->getAttributes();
    $sgid = $attributes['sso:validation']['sgid'];

    $em = $this->entityManager;
    $qb = $em->createQueryBuilder();
    $qb->select("u")
        ->from('ApplicationUserBundle:User', 'u')
        ->where('u.sgid = :sgid')
        ->AndWhere('u.status = 1')
        ->setParameter("sgid", $sgid);

    $result = $qb->getQuery()->getOneOrNullResult();

    //en cas où utilisateur est désactivée
    //Malgre que si il arrive a cette handler ça veut dire qu'il activé car le test se fait sur le bundle BeSimple
    if ($result == NULL) {
        return new RedirectResponse($this->router->generate('login'));
    }

    $session->set('userId', $result->getId());

    $response = new RedirectResponse('admin');

    return $response;
  }
}

4-现在在Application / UserBundle / Ressources / config / security_listeners.yml中定义一个安全列表器：

parameters:
    security.authentication.provider.sso.class: Application\UserBundle\Security\BeSimple\Authentication\Provider\AppAuthenticationProvider

services:
    security.authentication.provider.sso:
        class: %security.authentication.provider.sso.class%
        public: false
        arguments: ['', '@security.user_checker', '', '', false]

5- BeSimple配置应该是这样的：

be_simple_sso_auth:
admin_sso:
    protocol:
        id: cas
        version: 2
    server:
        id: cas
        login_url: https://adresse ip:8443/cas-server-webapp-4.0.0/login
        logout_url: https://adresse ip:8443/cas-server-webapp-4.0.0/logout
        validation_url: https://adresse ip:8443/cas-server-webapp-4.0.0/serviceValidate
services:

    spawned_user_provider:
        class:     Application\UserBundle\Security\BeSimple\SpawnedUserProvider\SsoUserProvider
    arguments: [@doctrine.orm.entity_manager, @session]

6-参数.yml

  be_simple.sso_auth.client.option.curlopt_ssl_verifypeer.value: false
  be_simple.sso_auth.client.option.curlopt_sslversion.value: 4 (Optionale)

7- security.yml

  main:
        pattern: ^/admin
        context: marketshare_context
        logout:
            path:   /admin/logout
            target: /
        #provider: sso
        trusted_sso:
            manager: admin_sso
            login_action: ApplicationUserBundle:TrustedSso:login
            logout_action: false
            login_path: /admin/login
            check_path: /admin/check
            always_use_default_target_path: true
            default_target_path: /admin/potentiel
            failure_path: /admin/logout

Answer 2

您还可以测试l3-team/CasBundle它似乎是最新的＆amp;比BeSimpleSSoBundle更活跃，文档更清晰。

它似乎也支持单点注销。

CAS认证Symfony2

2 个答案: