Question

我正在尝试获取已登录用户的数据（如姓名，性别，生日，个人资料图片等）。我尝试过以下两个代码，如下所示：

 //first: Create request for user's Facebook data
    FBRequest *request = [FBRequest requestForMe];

// Send request to Facebook
[request startWithCompletionHandler:^(FBRequestConnection *connection, id result, NSError *error) {
    NSLog(@"%@", error);
    if (!error) {
        // result is a dictionary with the user's Facebook data
        NSDictionary *userData = (NSDictionary *)result;
        NSLog(@"%@....",userData);
       _facebookID = userData[@"id"];
        _name = userData[@"name"];
        _location = userData[@"location"][@"name"];
        _gender = userData[@"gender"];
     _birthday = userData[@"birthday"];
        NSLog(@"%@",_name);


        _picutreURL = [NSURL URLWithString:[NSString stringWithFormat:@"https://graph.facebook.com/%@/picture?type=large&return_ssl_resources=1", _facebookID]];

        self.nameField.text=_name;
        self.profilePicture.image=[UIImage imageWithData:[NSData dataWithContentsOfURL:_picutreURL]];
        self.profileInfo.text=[NSString stringWithFormat:@"%@, Live in %@ , Born on %@",_gender,_location,_birthday];



    }
}];
// 2nd:Fetch user data
[FBRequestConnection
 startForMeWithCompletionHandler:^(FBRequestConnection *connection,
                                   id<FBGraphUser> user,
                                   NSError *error) {
     if (!error) {
         NSString *userInfo = @"";

         // Example: typed access (name)
         // - no special permissions required
         userInfo = [userInfo
                     stringByAppendingString:
                     [NSString stringWithFormat:@"Name: %@\n\n",
                      user.name]];

         // Example: typed access, (birthday)
         // - requires user_birthday permission
         userInfo = [userInfo
                     stringByAppendingString:
                     [NSString stringWithFormat:@"Birthday: %@\n\n",
                      user.birthday]];

         // Example: partially typed access, to location field,
         // name key (location)
         // - requires user_location permission
         userInfo = [userInfo
                     stringByAppendingString:
                     [NSString stringWithFormat:@"Location: %@\n\n",
                      user.location[@"name"]]];

         // Example: access via key (locale)
         // - no special permissions required
         userInfo = [userInfo
                     stringByAppendingString:
                     [NSString stringWithFormat:@"Locale: %@\n\n",
                      user[@"locale"]]];

         // Example: access via key for array (languages)
         // - requires user_likes permission
         if (user[@"languages"]) {
             NSArray *languages = user[@"languages"];
             NSMutableArray *languageNames = [[NSMutableArray alloc] init];
             for (int i = 0; i < [languages count]; i++) {
                 languageNames[i] = languages[i][@"name"];
             }
             userInfo = [userInfo
                         stringByAppendingString:
                         [NSString stringWithFormat:@"Languages: %@\n\n",
                          languageNames]];
         }

         // Display the user info
         NSLog(@"%@",userInfo);
     }
 }];

但是我在输出中得到空字符串并检测到此错误：

Error Domain=com.facebook.sdk Code=5 "The operation couldn’t be completed. (com.facebook.sdk error 5.)" UserInfo=0x9499320 {com.facebook.sdk:ParsedJSONResponseKey={
    body =     {
        error =         {
            code = 2500;
            message = "An active access token must be used to query information about the current user.";
            type = OAuthException;
        };
    };
    code = 400;
}, com.facebook.sdk:HTTPStatusCode=400}

我该怎么办？

Answer 1

我相信我遇到了同样的问题，而我刚开始工作的方式就是添加

FBSession.activeSession = fbSession;

初始处理程序成功返回后。（fbSession是你在facebook会话中拥有的任何变量。）我随便偶然发现了这一点（我想从另一个StackOverflow帖子）。但我没有在文档中看到它，并且通过grepping，它似乎不在任何Sample应用程序中。所以我的代码可能存在一个更大的问题，我没有看到？我很想知道其他人如何避免设置activeSession，并且仍能运行startForMeWithCompletionHandler。

OAuthException / code = 2500 / message =“必须使用活动访问令牌来查询有关当前用户的信息。”

1 个答案: