如何将jarray对象添加到JObject中

Question

如何将JArray添加到JObject？将jarrayObj更改为JObject时会出现异常。

parameterNames = "Test1,Test2,Test3";

JArray jarrayObj = new JArray();

foreach (string parameterName in parameterNames)
{
    jarrayObj.Add(parameterName);
}

JObject ObjDelParams = new JObject();
ObjDelParams["_delete"] = jarrayObj;

JObject UpdateAccProfile = new JObject(
                               ObjDelParams,
                               new JProperty("birthday", txtBday),
                               new JProperty("email", txtemail))

我需要以这种形式输出：

{
    "_delete": ["Test1","Test2","Test3"],
    "birthday":"2011-05-06",          
    "email":"dude@test.com" 
}

Answer 1

我发布代码时会发现两个问题。

1. parameterNames需要是一个字符串数组，而不仅仅是一个带逗号的字符串。
2. 您无法直接向JArray添加JObject;您必须将其放入JProperty并将 添加到JObject，就像使用“生日”和“电子邮件”属性一样。

更正后的代码：

string[] parameterNames = new string[] { "Test1", "Test2", "Test3" };

JArray jarrayObj = new JArray();

foreach (string parameterName in parameterNames)
{
    jarrayObj.Add(parameterName);
}

string txtBday = "2011-05-06";
string txtemail = "dude@test.com";

JObject UpdateAccProfile = new JObject(
                               new JProperty("_delete", jarrayObj),
                               new JProperty("birthday", txtBday),
                               new JProperty("email", txtemail));

Console.WriteLine(UpdateAccProfile.ToString());

输出：

{
  "_delete": [
    "Test1",
    "Test2",
    "Test3"
  ],
  "birthday": "2011-05-06",
  "email": "dude@test.com"
}

此外，为了将来参考，如果您在代码中遇到异常，如果您在问题中准确说明异常是什么，那么我们就不必猜测了。这使我们更容易为您提供帮助。

Answer 2

// array of animals
var animals = new[] { "cat", "dog", "monkey" };

// our profile object
var jProfile = new JObject
        {
            { "birthday", "2011-05-06" },
            { "email", "dude@test.com" }
        };

// Add the animals to the profile JObject
jProfile.Add("animals", JArray.FromObject(animals));

Console.Write(jProfile.ToString());

输出：

{    
  "birthday": "2011-05-06",
  "email": "dude@test.com",
  "animals": [
    "cat",
    "dog",
    "monkey"
  ]
}

Answer 3

var jObject = new JObject();
jObject.Add("birthday", "2011-05-06");
jObject.Add("email", "dude@test.com");
var items = new [] { "Item1", "Item2", "Item3" };
var jSonArray = JsonConvert.SerializeObject(items);
var jArray = JArray.Parse(jSonArray);
jObject.Add("_delete", jArray);

Answer 4

很简单，

JArray myarray = new JArray();
JObject myobj = new JObject();
// myobj.add(myarray); -> this is wrong. you can not add directly.

JProperty subdatalist = new JProperty("MySubData",myarray);
myobj.Add(subdata); // this is the correct way I suggest.