Question

我正在尝试了解路由器在Kohana中的工作原理。

我走向方法编译并面临困难......

这一行是什么原因：

 $expression = preg_replace('#'.Route::REGEX_ESCAPE.'#', '\\\\$0', $uri);

方法编译：

public static function compile($uri, array $regex = NULL)
    {
        // The URI should be considered literal except for keys and optional parts
        // Escape everything preg_quote would escape except for : ( ) < >
        $expression = preg_replace('#'.Route::REGEX_ESCAPE.'#', '\\\\$0', $uri);

        if (strpos($expression, '(') !== FALSE)
        {
            // Make optional parts of the URI non-capturing and optional
            $expression = str_replace(array('(', ')'), array('(?:', ')?'), $expression);
        }

        // Insert default regex for keys
        $expression = str_replace(array('<', '>'), array('(?P<', '>'.Route::REGEX_SEGMENT.')'), $expression);

        if ($regex)
        {
            $search = $replace = array();
            foreach ($regex as $key => $value)
            {
                $search[]  = "<$key>".Route::REGEX_SEGMENT;
                $replace[] = "<$key>$value";
            }

            // Replace the default regex with the user-specified regex
            $expression = str_replace($search, $replace, $expression);
        }

        return '#^'.$expression.'$#uD';
    }



const REGEX_ESCAPE  = '[.\\+*?[^\\]${}=!|]';

可以提示单独的文章，以帮助我理解吗？

Answer 1

// What must be escaped in the route regex
const REGEX_ESCAPE  = '[.\\+*?[^\\]${}=!|]';

// The URI should be considered literal except for keys and optional parts
// Escape everything preg_quote would escape except for : ( ) < >
$expression = preg_replace('#'.Route::REGEX_ESCAPE.'#', '\\\\$0', $uri);

这部分代码意味着所有字符（圆形和尖括号除外）都将被转义。它有助于检测特定路线中的问号或点。

\\\\$0

要使用反斜杠，您需要在regexpr中复制它。

使用此preg_replace的结果的几个例子：

test =＆gt;测试

test / =＆gt;测试/

// test / =＆gt; //测试/

//测试/！ =＆GT; //测试/＃！

// test /！＃$ =＆gt; //测试/！＃\ $

// test /！＃$％^＆amp; * aaa（）bbb =＆gt; ！//测试/＃\ $％\ ^＆安培; * AAA（）BBB

路由器::编译

1 个答案: