每当我尝试在我下面发布的调试器中运行代码时，它总是在设备指针上显示错误消息，例如变量check_d，check_re_h ......说
CXX0030：错误：无法计算表达式。
我是CUDA和视觉工作室的新手，所以任何帮助都将不胜感激。
#include<stdio.h>
//#include<stddef.h>
//#include"sourceannotations.h"
#include<cuda.h>
//#include<cutil.h>
#include<cuda_runtime_api.h>
#include<cuda_runtime.h>
#include<iostream>
#include<device_launch_parameters.h>
#include <cmath>
#include<cstdlib>
#include<time.h>
#include<string>
#include<vector>
#define PI 3.141592654
using namespace std;
// #define checkCudaErrors(err) __checkCudaErrors (err, __FILE__, __LINE__)
struct vertex
{
float x,y,z,h;
// struct triangle* _triangle ;
// struct octree* tree ;
vertex():x(0),y(0),z(0),h(1){};//,tree(NULL)/*, _triangle(NULL)*/{}
vertex(float x, float y, float z, float h=0):x(x),y(y),z(z),h(h){};//,/*_triangle(NULL),*/tree(NULL){}
};
struct triangle
{
vertex v1,v2,v3;
triangle(){
//v1._triangle = v2._triangle = v3._triangle = this;
}
};
//if the function is decleared as global then it is run by multiple threads parallelly
__global__ void VecAdd(/*int *A, int *B, int *C,*/ int *check)
{
//int count =0;
int idx = blockIdx.x+ threadIdx.x;
// int count=0;
//int tx = threadIdx.x;
//this is for checking the value of idx
check[idx] = idx;
//C[idx] = A[idx] + B[idx];
}
__global__ void check(float mat[][4],vertex *a,float *re,int *index)
{
// float re[4];
float sum =0;
int idx = blockIdx.x+ threadIdx.x;
// index[idx] = idx;
//int count=0;
//int tx = threadIdx.x;
/*for (int i=0; i<4; i++)
{*/
sum += mat[idx][0]* a->x;
sum += mat[idx][1]* a->y;
sum += mat[idx][2]* a->z;
sum += mat[idx][3];
/*sum += *((float*)mat+idx+4*0)* a->x;
sum += *((float*)mat+idx+4*1)* a->y;
sum += *((float*)mat+idx+4*2)* a->z;
sum += *((float*)mattr+idx+4*3);*/
/*}*/
re[idx] = sum;
}
int main()
{
//float res[4][4];
triangle t1;
t1.v1.x = 2;
t1.v1.y = 1.33512;
t1.v1.z = 5.849567;
t1.v2.x = 2;
t1.v2.y = -1.33512;
t1.v2.z = 5.849567;
t1.v3.x = 2;
t1.v3.y = 0;
t1.v3.z = 5;
vertex *check_d;
vertex *check_h;
float *check_re_d;
float *check_re_h;
float translation_check_d[4][4];
float translation_check_h[4][4] = {{1, 0, 0, -t1.v1.x},
{0, 1, 0, -t1.v1.y},
{0, 0, 1, -t1.v1.z},
{0 ,0 ,0, 1}};
check_h = new vertex(1,-4,3);
check_re_h = new float[4];
cudaMalloc((void**)&check_d,sizeof(vertex));
cudaMalloc((void**)&check_re_d,4*sizeof(float));
cudaMemcpy(check_d,check_h,sizeof(vertex),cudaMemcpyHostToDevice);
cudaMemcpy(check_re_d,check_re_h,4*sizeof(float),cudaMemcpyHostToDevice);
size_t dPitch;
cudaMallocPitch((void**)translation_check_d,&dPitch,4*sizeof(float),4);
cudaMemcpy2D(translation_check_d,dPitch,translation_check_h,dPitch,4*sizeof(float),4,cudaMemcpyHostToDevice);
int *index_h = NULL;
int *index_d = NULL;
index_h = new int[4];
cudaMalloc((void**)&index_d,4*sizeof(int));
cudaMemcpy(index_d,index_h,sizeof(int),cudaMemcpyHostToDevice);
check<<<1,4>>>(translation_check_d,check_d,check_re_d,index_d);
//VecAdd<<<10,1>>>(index_d);
cudaMemcpy(check_re_h,check_re_d,4*sizeof(float),cudaMemcpyDeviceToHost);
cudaMemcpy(index_h,index_d,4*sizeof(int),cudaMemcpyDeviceToHost);
std::cout<<"These are the value"<<"INDEX: "<<index_h[0]<<" x: "<<check_re_h[0]<<"\n";
std::cout<<"These are the value"<<"INDEX: "<<index_h[1]<<" x: "<<check_re_h[1]<<"\n";
std::cout<<"These are the value"<<"INDEX: "<<index_h[2]<<" x: "<<check_re_h[2]<<"\n";
cudaFree(check_d);
cudaFree(check_re_d);
cudaFree(index_d);
cudaFree(check_h);
cudaFree(check_re_h);
cudaFree(index_h);
int a;
cin>>a;
return 0;
}
答案 0 :(得分：1)
您的代码存在一些问题，从设备内存分配（也是分配分配）开始到2D内存副本。以下是“固定”代码。请注意，我已在评论中澄清了修改
#include<stdio.h>
#include<cuda.h>
#include<cuda_runtime_api.h>
#include<cuda_runtime.h>
#include<iostream>
#include<device_launch_parameters.h>
#include <cmath>
#include<cstdlib>
#include<time.h>
#include<string>
#include<vector>
#include<conio.h>
#define PI 3.141592654
using namespace std;
/*****************/
/* VERTEX STRUCT */
/*****************/
struct vertex
{
float x,y,z,h;
vertex():x(0),y(0),z(0),h(1){};//,tree(NULL)/*, _triangle(NULL)*/{}
vertex(float x, float y, float z, float h=0):x(x),y(y),z(z),h(h {};//,/*_triangle(NULL),*/tree(NULL){}
};
/*******************/
/* TRIANGLE STRUCT */
/*******************/
struct triangle
{
vertex v1,v2,v3;
triangle(){ }
};
// The kernel function interface should contain also the pitch value. I have removed the int* index parameter (not needed now).
// I have also updated the mat parameter.
//__global__ void check(float mat[][4],vertex *a,float *re,int *index)
__global__ void check(float** mat,vertex *a,float *re,size_t pitch)
{
float sum = 0;
int idx = threadIdx.x;
float* row = (float*)((char*)mat + idx*pitch);
printf("row %i column 0 value %f \n",idx,row[0]);
printf("row %i column 1 value %f \n",idx,row[1]);
printf("row %i column 2 value %f \n",idx,row[2]);
printf("row %i column 3 value %f \n",idx,row[3]);
sum += mat[idx][0]* a->x;
sum += mat[idx][1]* a->y;
sum += mat[idx][2]* a->z;
sum += mat[idx][3];
re[idx] = sum;
}
/********/
/* MAIN */
/********/
int main()
{
triangle t1;
t1.v1.x = 2;
t1.v1.y = 1.33512;
t1.v1.z = 5.849567;
t1.v2.x = 2;
t1.v2.y = -1.33512;
t1.v2.z = 5.849567;
t1.v3.x = 2;
t1.v3.y = 0;
t1.v3.z = 5;
vertex* check_h = new vertex(1,-4,3);
vertex* check_d; cudaMalloc((void**)&check_d,sizeof(vertex));
float* check_re_h = new float[4];
float* check_re_d; cudaMalloc((void**)&check_re_d,4*sizeof(float));
cudaMemcpy(check_d,check_h,sizeof(vertex),cudaMemcpyHostToDevice);
cudaMemcpy(check_re_d,check_re_h,4*sizeof(float),cudaMemcpyHostToDevice);
float translation_check_h[4][4] = {{1, 0, 0, -t1.v1.x},{0, 1, 0, -t1.v1.y},{0, 0, 1, -t1.v1.z},{0 ,0 ,0, 1}};
//This is a host-side static array definition.
//float translation_check_d[4][4];
float** translation_check_d;
// This is a wrong usage of cudaMallocPitch. The correct syntax is cudaMallocPitch(void** devPtr, size_t* pitch, size_t widthInBytes, size_t height).
// size_t dPitch; cudaMallocPitch((void**)translation_check_d,&dPitch,4*sizeof(float),4);
size_t dPitch; cudaMallocPitch(&translation_check_d,&dPitch,4*sizeof(float),4);
// I have fixed also the cudaMemcpy2D call, see below.
//cudaMemcpy2D(translation_check_d,dPitch,translation_check_h,dPitch,4*sizeof(float),4,cudaMemcpyHostToDevice);
cudaMemcpy2D(translation_check_d, dPitch, translation_check_h, 4*sizeof(float), 4*sizeof(float), 4, cudaMemcpyHostToDevice);
// Useless
//int *index_h = new int[4];
//int *index_d = NULL; cudaMalloc((void**)&index_d,4*sizeof(int));
//cudaMemcpy(index_d,index_h,sizeof(int),cudaMemcpyHostToDevice);
//check<<<1,4>>>(translation_check_d,check_d,check_re_d,index_d);
check<<<1,4>>>(translation_check_d,check_d,check_re_d,dPitch);
// I haven't checked the rest, being it straightforward.
getch();
return 0;
}