Question

我有两张表如下：

- tblSaler

    SalerID  |  SalerName | 
    ----------------------|
    1        |  sothorn   |
    ----------------------|
    2        |  Daly      |  
    ----------------------|
    3        |  Lyhong    |
    ----------------------|
    4        | Chantra    |
    ----------------------|

- tblProduct

ProductID  | Product  | SalerID |
--------------------------------|
1          | Pen      | 3       |
--------------------------------|
2          | Book     | 2       |
--------------------------------|
3          | Phone    | 3       |
--------------------------------|
4          | Computer | 1       |
--------------------------------|
5          | Bag      | 3       |
--------------------------------|
6          | Watch    | 2       |
--------------------------------|
7          | Glasses  | 4       |
--------------------------------|

我需要的结果是：

sothorn | 1
Daly    | 2
Lyhong  | 3
Chantra | 1

我试过这个：

    $this->db->select('count(SalerName) as sothorn where tblSaler.SalerID = 1, count(SalerName) as Daly where tblSaler.SalerID = 2, count(SalerName) as Lyhong where tblSaler.SalerID = 3, count(SalerName) as Chantra where tblSaler.SalerID = 4');
    $this->db->from('tblSaler');
    $this->db->join('tblProduct', 'tblSaler.SalerID = tblProduct.SalerID');

Answer 1

您可以将此查询用于此

SELECT
  tblSaler.SalerName,
  count(tblProduct.ProductID) as Total
FROM tblSaler
  LEFT JOIN tblProduct
    ON tblProduct.SalerID = tblSaler.SalerID
GROUP BY tblSaler.SalerID

以下是此

的有效记录

$select =   array(
                'tblSaler.SalerName',
                'count(tblProduct.ProductID) as Total'
            );  
$this->db
        ->select($select)
        ->from('tblSaler')
        ->join('tblProduct','Product.SalerID = tblSaler.SalerID','left')
        ->group_by('tblSaler.SalerID')
        ->get()
        ->result_array();

Demo

输出

_____________________
| SALERNAME | TOTAL |
|-----------|-------|
|   sothorn |     1 |
|      Daly |     2 |
|    Lyhong |     3 |
|   Chantra |     1 |
_____________________

Answer 2

请尝试此代码。它对我来说很好，它也会帮助你。

$this->db->select('SalerName, count(*)');
$this->db->from('tblSaler');        
$this->db->join('tblProduct', 'tblSaler.SalerID = tblProduct.SalerID'); 
$this->db->group_by('tblSaler.SalerID');       
$query = $this->db->get();

您可以使用下面的这一行获得整个SQL查询

$query = $this->db->get(); 
echo $this->db->last_query();

Answer 3

试试这个

$this->db->select('SalerName, count(*)'); 
$this->db->from('tblSaler'); 
$this->db->join('tblProduct', 'tblSaler.SalerID = tblProduct.SalerID');
$this->db->group('SalerID');

Answer 4

   ## try this ##
   $this->db->select($column_name);
    $this->db->where($column_name,$type);
    $q=$this->db->get($table_name);
    $count=$q->result();
    return count($count);'

选择，计数和使用codeigniter和mysql的位置

4 个答案: