使用Ajax表单的MVC 4 Razor更新foreach循环

时间:2013-10-28 02:49:47

标签: ajax asp.net-mvc jquery asp.net-mvc-4 razor

从哪里开始...我可以在互联网上找到类似的东西,但是它们似乎永远不会以我想要做某事的具体方式工作。我尝试了有部分观点和没有部分观点,但收效甚微。

快速纲要:我有一个带有Ajax表单的强类型视图。在表单下面,我有一个重复代码块的foreach循环。我需要能够从表单选项(过滤器)更新代码块。

这是我的观点,'FindATeacher.cshtml',因为它目前的情况(在尝试了许多不同的想法之后):

@model Teachers.Models.OmniModel
@{
    ViewBag.Title = "FindATeacher";
    Layout = "~/Views/Shared/_Layout.cshtml";

}
<h2>Find a Teacher</h2>
@using (Ajax.BeginForm("FilterTeachers", "Home", new AjaxOptions { HttpMethod = "Post", OnSuccess = "onSuccess" }))
{
    <div id="ContentFilter">
        <div class="filterLabels">
            <p>Search by Name</p>
            <p>Filter By Instrument</p>
            <p>Filter By City</p>
        </div>
        <div class="filterObjects">
            <p>
                <input type="text" id="nameTXT" />
                <button type="submit" id="findButton">find</button>
            </p>
            <p>@Html.DropDownList("InstrumentID", (SelectList)Model.Instruments, "-- Select an Instrument --", new { id = "instrumentDD" })</p>
            <p>@Html.DropDownList("CityID", (SelectList)Model.Cities, "-- Select a City --", new { id = "cityDD" })</p>
        </div>
    </div>
}
<hr />
@foreach (var r in Model.Teachers)
{
    <div id="ContentResults">
        <div id="avatar">
            <img src="i" />
        </div>

        <div id="demographics">
            <h6>@r.Teacher</h6>
            <strong>@r.StudioName</strong>
            <p><a href="#">@r.URL</a></p>
            <p>@r.StreetAddress</p>
            <p>@r.City, @r.AddressStateID @r.Zip</p>
            <p>@r.Phone</p>
            <p>@r.EmailAddress</p>
        </div>
        <div id="studioDetails">
            <p><strong>Instrument(s) Taught</strong></p>
            <p>
                @{
    var instrumentString = r.Instruments.Aggregate("", (a, b) => a + b.Instrument + ", ");
    if (instrumentString.Length != 0)
    {
        instrumentString = instrumentString.Remove(instrumentString.LastIndexOf(","));
    }
                }
                @instrumentString
            </p>
            <br />

            @if (r.Information != "" && r.Information != null)
            {
                <p><strong>Information</strong></p>
                <p>@r.Information</p>
            }
        </div>
    </div>
}

现在这是我的控制器。我在Controller中正确地得到了结果,只是没有更新代码块:

public ActionResult FindATeacher()
        {
            Model.Instruments = new SelectList(TeacherService.GetInstrumentList(0),"InstrumentID","Instrument");
            Model.Cities = new SelectList(TeacherService.GetCityList(),"CityID","City");
            Model.Teachers = TeacherService.GetTeacherList("", 0);
            return View(Model);
        }

        [HttpPost]
        public JsonResult FilterTeachers(String teacherName, String instrumentID, String cityID)
        {
            Model.Teachers = TeacherService.GetTeacherList("John", 0, 0);
            return Json(Model.Teachers);
        }

感谢。

2 个答案:

答案 0 :(得分:14)

@VishalVaishya提出了正确的想法,但有一种更简单的方法,它不涉及自定义的javascript代码:AjaxOptions有一个UpdateTargetId属性,AJAX工具包将解释为表示您希望使用发送的结果更新给定目标从控制器回来。

FindATeacher.cshtml:

@using (Ajax.BeginForm("FilterTeachers", "Home", new AjaxOptions { 
    HttpMethod = "Post", UpdateTargetId = "TeacherList" }))
{
    ...
}
<hr />
<div id="TeacherList">
    @Partial("TeacherList", Model.Teachers)
</div>

TeacherList.cshtml

@model IEnumerable<Teacher>
@foreach(var teacher in Model)
{
   ...
}

控制器操作:

    [HttpPost]
    public ActionResult FilterTeachers(String teacherName, String instrumentID, String cityID)
    {
        Model.Teachers = TeacherService.GetTeacherList(teacherName, instrumentID, cityID);
        return PartialView("TeacherList", Model.Teachers);
    }

答案 1 :(得分:3)

您可以尝试以下方法:

将您的foreach循环分成另一个局部视图。 并在filter / click事件上加载部分视图,并将过滤后的参数传递给controller-action。

JS更改事件代码将是这样的:

var teacherName = ''; //get your selected teachername
var instrumentID = ''; //get your selected instrumentid
var cityID = ''; //get your selected city id

var url = '@Url.Action("FilterTeachers", "ControllerName", new { teacherName = "teacher-Name", instrumentID="instrument-ID", cityID="city-ID" })';

url = url.replace("teacher-Name", teacherName).replace("instrument-ID", instrumentID).replace("city-ID", cityID);

$('#result').load(url);