Question

我的问题就像Split string on spaces in Java, except if between quotes (i.e. treat \"hello world\" as one token)，但是以NSIS的方式。希望没有任何外部插件。

如何根据空格拆分字符串，但将引用的子字符串作为   一个字？

示例：
Location "Welcome to india" Bangalore Channai "IT city"  Mysore
它应该作为
存储在ArrayList中
Location
Welcome to india
Bangalore
Channai
IT city
Mysore

Answer 1

没有插件没有数组支持，所以我省略了数组部分。

可以使用NSIS中的3个基本字符串函数（StrLen，StrCpy和StrCmp）执行任何字符串操作：

!include LogicLib.nsh
Function SplitArg
Exch $0 ; str
Push $1 ; inQ
Push $3 ; idx
Push $4 ; tmp
StrCpy $1 0
StrCpy $3 0
loop:
    StrCpy $4 $0 1 $3
    ${If} $4 == '"'
        ${If} $1 <> 0 
            StrCpy $0 $0 "" 1
            IntOp $3 $3 - 1
        ${EndIf}
        IntOp $1 $1 !
    ${EndIf}
    ${If} $4 == '' ; The end?
        StrCpy $1 0
        StrCpy $4 ' '
    ${EndIf} 
    ${If} $4 == ' '
    ${AndIf} $1 = 0
        StrCpy $4 $0 $3
        StrCpy $1 $4 "" -1
        ${IfThen} $1 == '"' ${|} StrCpy $4 $4 -1 ${|}
        killspace:
            IntOp $3 $3 + 1
            StrCpy $0 $0 "" $3
            StrCpy $1 $0 1
            StrCpy $3 0
            StrCmp $1 ' ' killspace
        Push $0 ; Remaining
        Exch 4
        Pop $0
        StrCmp $4 "" 0 moreleft
            Pop $4
            Pop $3
            Pop $1
            Return
        moreleft:
        Exch $4
        Exch 2
        Pop $1
        Pop $3
        Return
    ${EndIf}
    IntOp $3 $3 + 1
    Goto loop
FunctionEnd


Section
push 'Location "Welcome to india" Bangalore Channai "IT city"  Mysore'
loop:
    call SplitArg
    Pop $0
    StrCmp $0 "" done
    DetailPrint Item=|$0|
    goto loop
done:
SectionEnd

使用空格计算和拆分字符串，除非在NSIS中引用之间

1 个答案: