我有一个简单的“培训”项目,必须在Windows中显示优先级机制。
这是我的C ++代码:
#include <stdio.h>
#include <windows.h>
DWORD WINAPI Thread1(LPVOID);
int stop;
int sleep = 10000;
struct params {
int num;
bool* runflg;
};
long long counters[7] = {0,0,0,0,0,0,0};
int priority[7] = {THREAD_PRIORITY_IDLE, THREAD_PRIORITY_LOWEST, THREAD_PRIORITY_BELOW_NORMAL, THREAD_PRIORITY_NORMAL, THREAD_PRIORITY_ABOVE_NORMAL, THREAD_PRIORITY_HIGHEST, THREAD_PRIORITY_TIME_CRITICAL};
int main(int argc, char* argv[])
{
int thrds;
if (argc < 2) stop = 5;
else stop = atoi(argv[1]);
bool runFlag = true;
__int64 end_time;
LARGE_INTEGER end_time2;
HANDLE tm1 = CreateWaitableTimer(NULL, false, NULL);
end_time = -1 * stop * 10000000;
end_time2.LowPart = (DWORD) (end_time & 0xFFFFFFFF);
end_time2.HighPart = (LONG) (end_time >> 32);
SetWaitableTimer(tm1, &end_time2, 0,NULL, NULL, false);
//SetPriorityClass(GetCurrentProcess(), HIGH_PRIORITY_CLASS);
printf("process priority = %d \n", GetPriorityClass(GetCurrentProcess()));
SetProcessPriorityBoost(GetCurrentProcess(), true);
for (int i = 0; i < 7; i++) {
DWORD targetThreadId;
params* param = (params*)malloc(sizeof(params));
param->num = i;
param->runflg = &runFlag;
HANDLE t1 = CreateThread(NULL, 0, Thread1, param, 0, &targetThreadId);
SetThreadPriority(t1, priority[i]); //задание приоритета
PBOOL ptr1 = (PBOOL)malloc(sizeof(BOOL));
GetThreadPriorityBoost(t1, ptr1);
SetThreadPriorityBoost(t1, true); //запрет динамического изм. приоритета
CloseHandle(t1);
}
WaitForSingleObject(tm1,INFINITE);
runFlag = false;
CloseHandle(tm1);
printf("\n");
for (int i = 0; i < 7; i++) {
printf("%d - %ld\n",i, counters[i]);
}
return 0;
}
DWORD WINAPI Thread1(LPVOID prm)
{
params arg = *((params*)prm);
printf("thread # %d priority = %d \n", arg.num, GetThreadPriority(GetCurrentThread()));
while(1) {
counters[arg.num]++;
Sleep(0);
if(*(arg.runflg) == false)
break;
}
return 0;
}
在代码中,我创建了7个具有不同线程优先级的线程。每个线程都有自己的计数器。该程序应该运行大约5秒钟,然后控制台必须显示线程的优先级及其值。 当我在一年前在Win XP 32上完成它时,一切正常 - 优先级较低的线程具有较小的计数器值。但现在我有这样奇怪的结果:
process priority = 32
thread # 0 priority = -15
thread # 1 priority = -2
thread # 2 priority = -1
thread # 3 priority = 0
thread # 4 priority = 1
thread # 5 priority = 2
thread # 6 priority = 15
0 - 5401405
1 - 5726804
2 - 6676367
3 - 8320768
4 - 3223481
5 - 3085247
6 - 3177885
为什么优先级不起作用,计数器有这么奇怪的值(没有按升序排序)?
答案 0 :(得分:1)
@Zilog如何回答这个问题 - 一些奇怪的行为的原因在于MULTI-procces CPU。
如果有人想看看具有不同优先级的线程如何工作 - 它们必须使用特定的功能(如系统工作的monitor \ profilier),或者在程序中使用特殊的功能,只使用一个处理器。