Question

我尝试将awk命令的输出分配给变量：

USERS=$(awk '/\/X/ {print $1}' <(w))

此行是以下脚本的一部分：

#!/bin/sh

INTERFACE=$1 # The interface which is brought up or down
STATUS=$2 # The new state of the interface

case "$STATUS" in
    up) # $INTERFACE is up

        if pidof dropbox; then
          killall dropbox
        fi

        USERS=$(awk '/\/X/ {print $1}' <(w))

        for user in $USERS; do
            su -c "DISPLAY=$(awk '/\/X/ {print $11}' <(w)) dropboxd &" $user
        done
        ;;
    down) # $INTERFACE is down
        ;;
esac

但是，我收到以下错误：

script: command substitution: line 14: syntax error near unexpected token `('
script: command substitution: line 14: `awk '/\/X/ {print $1}' <(w))'

所有括号均已关闭。语法错误在哪里？

Answer 1

我假设是因为您使用#!/bin/sh而不是#!/bin/bash进程替换不可用（或者您有一个不支持进程替换的bash版本，前4 .XX）。切换到bash或只管道w到awk命令：

USERS=$(w | awk '/\/X/ {print $1}')

awk：意外令牌附近的语法错误`（''

1 个答案: