我的代码如下(我不知道为什么它没有缩进):
def move_joker_2(deck):
#start checking every card in the deck until the position of
#JOKER2 is found
#we start from position 0
position = 0
while deck [position] != JOKER2:
position = position + 1
#the new position for JOKER2
if position < len (deck) - 3:
new_position = position + 2
elif position == len (deck) - 2:
new_position = 0
else:
new_position = 1
#to reorganize deck, we need 2 things
# 1.) a list of the cards above JOKER2 after moving the cards
# 2.) a list of the cards below JOKER2 after moving the cards
#depending of new_position, there are 3 possible new decks
if new_position == 0:
#no cards above, JOKER2 will become the top card
cards_above = []
#every other card will be below it
cards_below = deck
#remove JOKER2, since we moved it
cards_below.pop(position)
elif new_position == 1:
#the only card above JOKER2 will be the top card
cards_above = [deck[0]]
#every other card up except the last one will be below it
cards_below = deck [new_position:len(deck)-1]
else:
cards_above = deck[0:new_position+1]
#remove JOKER2, since we moved it
cards_above.pop(position)
cards_below = deck [new_position+1:]
#final deck
deck = cards_above + [JOKER2] + cards_below
我的代码收到一个字符串列表并最终改变它......
但为什么不改变原始列表呢? 例如:
deck = [1,3,27,8,9] move_joker_2(甲板)
考虑到JOKER2是27,它应该改变列表: [1,3,8,9,27]
但每当我打电话给它时,它都没有改变......
答案 0 :(得分:6)
deck = cards_above + [JOKER2] + cards_below
不会更改deck
的内容。
它创建了一个新列表,deck
引用了新列表。
要更改桌面使用切片表示法的内容,例如deck[:] = cards_above + [JOKER2] + cards_below
。
>>> def f1(deck):
... deck = [1,2,3] # This does not change the `deck` passed.
# This just create a local variable `deck`.
...
>>> def f2(deck):
... deck[:] = [4,5,6] # This change the `deck` passed.
...
>>> deck = [0]
>>> f1(deck)
>>> deck
[0]
>>> f2(deck)
>>> deck
[4, 5, 6]
答案 1 :(得分:1)
deck
只是一个带有参考副本的变量,因此当您指定
deck = ....
创建新对象并将其引用分配给deck变量。这些是c ++意义上的不引用,它们是始终引用的副本。
一个可行的解决方法是使用
deck[:] = ...
更新对象的内容,而不仅仅是参考值