Question

这是我试图从文件中读取的代码片段。我的文件目前有4行，但读取这些行后代码不会出现在循环中。

    public class ViewServlet extends HttpServlet {
private static final long serialVersionUID = 1L;

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    doPost(request,response);
}

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException{
    System.out.println("Logging in..");
    // retrieving values entered in form
    String uname = request.getParameter("uname");
    String pwd = (String) request.getParameter("pwd");

    if (uname.equals("admin") && pwd.equals("admin")) {

        try {
            viewDetails();
            System.out.println("Redirecting to view page..");
            response.sendRedirect("view.jsp");
        } catch (Exception e) {

        }
    } 
        }

public void viewDetails() throws Exception{
    System.out.println("Reading Data..");
    BufferedReader input = new BufferedReader(new FileReader("H:/Workspace/teamRecordsApp/WebContent/records.txt"));
    String record;
    String[] split =new String[5];

    ArrayList cuid = new ArrayList();
    ArrayList fname = new ArrayList();
    ArrayList lname = new ArrayList();
    ArrayList mobile = new ArrayList();
    ArrayList desk = new ArrayList();
    int count = 0;
    while((record=input.readLine()) != null){
        split = record.split(",");
        System.out.println("Record is : "+split[0]+","+split[1]+","+split[2]+","+split[3]+","+split[4]);
        cuid.add(split[0]);
        fname.add(split[1]);
        lname.add(split[2]);
        mobile.add(split[3]);
        desk.add(split[4]);
        count = count+1;

    }
    input.close();
    System.out.println("Reading Done...");
    Utils utils = new Utils();
    utils.setCuid(cuid);
    utils.setFname(fname);
    utils.setLname(lname);
    utils.setMobile(mobile);
    utils.setDesk(desk);
    utils.setCount(count);
    System.out.println("Total records : "+count);


}

}

*现在添加了整个servlet类。

控制台显示：

Logging in..
Reading Data..
Record is : 12,e,e,1234567890,1234
Record is : 12,e,e,1234567890,1234
Record is : 12,e,e,1234567890,1234

记录是：12，e，e，1234567890,123

在文件中添加printStackTrace（）后，我收到的异常将在下面附上。正如@Pshemo所说，最后一行是空的是给出了这个例外。我无法通过查看文件并添加printStackTrace来解决这个问题。非常感谢@Pshemo和其他人的帮助！

java.lang.ArrayIndexOutOfBoundsException: 1
at ViewServlet.viewDetails(ViewServlet.java:54)
at ViewServlet.doPost(ViewServlet.java:31)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:637)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:857)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
at java.lang.Thread.run(Unknown Source)

Answer 1

因为你在try-catch块中调用viewDetails();，但你没有处理异常（你甚至不打印它的堆栈跟踪）

} catch (Exception e) {
    //nothing here... :/
}

我认为在"Reading Done..."按摩之前，你的循环中会抛出异常。许多事情都可能导致异常，例如，如果你的文件在你的循环中有一些空行你会读它""并将它拆分在,上，这将创建一个元素数组{""}然后使用split[1]即可获得IndexOutOfBoundException。但这只是其中一种可能性。要确保您的代码添加

有什么问题

e.printStackTrace();

到catch (Exception e)区块。

读取文件时无限循环

记录是：12，e，e，1234567890,123

1 个答案: