Question

一点背景知识。我试图在创建时预先填充我的Document模型的属性。为了做到这一点，我使用的是“current_user”帮助器的基本形式。

但是，当我尝试设置@document.creator = current_user.id时，出现ActiveRecord::AssociationTypeMismatch ... User expected, got Fixnum错误。

我承认我不确定为什么。有人能够澄清究竟是什么不正确吗？

相关型号和控制器是：

class User < ActiveRecord::Base
  include Authority::UserAbilities
  attr_accessible :email, :name
  has_many :authorizations
end

和

class Document < ActiveRecord::Base
  has_one :creator, class_name: "User", foreign_key: "id", primary_key: "creator"
  attr_accessible :document_subject, document_keywords
  def as_json(options={})
    {
        :document_subject => document_subject,
        :document_keywords => document_keywords,
    }
  end
end

和

class ApplicationController < ActionController::Base
  protect_from_forgery
  private
  def current_user
    @current_user ||= User.find(session[:user_id]) if session[:user_id]
  end
  helper_method :current_user
end

和

class DocumentsController < ApplicationController

def create
    @document = Document.new(params[:document])
    @document.creator = current_user.id
    @document.save

    respond_to do |format|
      if @document.save
        format.json { render json: @document, status: :created, location: @document }
      else
        format.json { render json: @document.errors, status: :unprocessable_entity }
      end
    end
  end

和DB模式（写入DB）

PRAGMA table_info(users);
[,
 {
  "cid": 0,
  "name": "id",
  "type": "INTEGER",
  "notnull": 1,
  "dflt_value": null,
  "pk": 1
 },
 {
  "cid": 1,
  "name": "name",
  "type": "varchar(255)",
  "notnull": 0,
  "dflt_value": null,
  "pk": 0
 },
 {
  "cid": 2,
  "name": "email",
  "type": "varchar(255)",
  "notnull": 0,
  "dflt_value": null,
  "pk": 0
 },
 {
  "cid": 3,
  "name": "created_at",
  "type": "datetime",
  "notnull": 1,
  "dflt_value": null,
  "pk": 0
 },
 {
  "cid": 4,
  "name": "updated_at",
  "type": "datetime",
  "notnull": 1,
  "dflt_value": null,
  "pk": 0
 },
 {
  "cid": 5,
  "name": "active",
  "type": "boolean",
  "notnull": 1,
  "dflt_value": 'f',
  "pk": 0
 }
]

PRAGMA table_info(Documents);

[,
 {
  "cid": 0,
  "name": "id",
  "type": "INTEGER",
  "notnull": 1,
  "dflt_value": null,
  "pk": 1
 },
 {
  "cid": 1,
  "name": "created_at",
  "type": "datetime",
  "notnull": 1,
  "dflt_value": null,
  "pk": 0
 },
 {
  "cid": 2,
  "name": "updated_at",
  "type": "datetime",
  "notnull": 1,
  "dflt_value": null,
  "pk": 0
 },
 {
  "cid": 3,
  "name": "creator",
  "type": "integer",
  "notnull": 0,
  "dflt_value": null,
  "pk": 0
 },
{
  "cid": 4,
  "name": "document_subject",
  "type": "varchar(255)",
  "notnull": 0,
  "dflt_value": null,
  "pk": 0
 },
{
  "cid": 5,
  "name": "document_keywords",
  "type": "varchar(255)",
  "notnull": 0,
  "dflt_value": null,
  "pk": 0
 }
]

Answer 1

期待Active Record对象本身而不是ID。您只需要执行@document.creator = current_user。

Answer 2

Beerlington的回复按照描述进行，但仍然不是我想要达到的理想解决方案。

我最终改变了策略：我没有在文档模型中添加创建者字段，而是使用{}创建文档时使用rolify角色。

@document.save
current_user.add_role :creator, @document

DocumentsController中的ActiveRecord :: AssociationTypeMismatch

2 个答案: