Question

我正在使用AFHTTPRequestOperationManager来处理POST请求。现在我故意输入不正确的信息来处理400错误代码。现在，Web服务实际上返回一个JSON，其中包含一条消息，向用户解释他们做错了什么。我非常想让这个JSON在UIAlertView中显示消息。但是，失败块：

[operationManager POST:ServerURL parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
    NSLog(@"Success: Status Code: %d", operation.response.statusCode);
}
 failure:^(AFHTTPRequestOperation *operation, NSError *error) {
     NSLog(@"Failed: Status Code: %d", operation.response.statusCode);
 }];

不传递响应对象，如成功块中的那个。那么有谁知道如何访问Web服务返回的带有400错误的JSON？ NSError *error只给我Request failed: bad request (400)而不是JSON返回。

任何帮助将不胜感激，˙Mike

Answer 1

查看- responseObject的代码，似乎HTTP错误阻止了它的填充。您可以直接抓取responseData并自行解析，但我会说这是一个错误或一个很好的增强请求。（在确定是否应该尝试构建响应对象时，看起来- responseObject可能应该检查self.responseSerializationError，而不是self.error。）

Answer 2

您可以执行以下任一解决方案

1）设置acceptableStatusCodes接受400 statusCode，然后处理成功块

manager.responseSerializer.acceptableStatusCodes = [NSIndexSet indexSetWithIndex:400];

2）创建一个自定义的ResponseSerializer，就像这个JSONResponseSerializerWithData一样，将responseObject插入到NSError userInfo中，并在失败块中处理

专业提示：AFNetworking是开源，只需看一下AFHTTPRequestOperation的方法

setCompletionBlockWithSuccess:failure:

responseObject

error

Answer 3

以下代码代表我：

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    manager.responseSerializer = [AFJSONResponseSerializer serializer];
    manager.requestSerializer = [AFJSONRequestSerializer serializer];

    [manager.requestSerializer setValue:@"parse-application-id-removed" forHTTPHeaderField:@"X-Parse-Application-Id"];
    [manager.requestSerializer setValue:@"parse-rest-api-key-removed" forHTTPHeaderField:@"X-Parse-REST-API-Key"];
    [manager.requestSerializer setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    manager.securityPolicy.allowInvalidCertificates = YES;

    NSString *URLString = [NSString stringWithFormat:@"%@/%@", BASE_URL,methodName];



    [manager POST:URLString parameters:requestDict success:^(AFHTTPRequestOperation *operation, id responseObject)
    {
        NSLog(@"JSON: %@", responseObject);

        [myDelegate StopIndicator];
    } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
        NSLog(@"Error: %@", error);
        [myDelegate StopIndicator];
    }];

Answer 4

我在AFNetworking中也面临同样的问题，而不是使用

- (NSURLSessionDataTask *)POST:(NSString *)URLString
                parameters:(id)parameters
                  progress:(void (^)(NSProgress * _Nonnull))uploadProgress
                   success:(void (^)(NSURLSessionDataTask * _Nonnull, id _Nullable))success
                   failure:(void (^)(NSURLSessionDataTask * _Nullable, NSError * _Nonnull))failure

请尝试使用那个： -

- (NSURLSessionDataTask *)POST:(NSString *)URLString
                parameters:(id)parameters
 constructingBodyWithBlock:(void (^)(id <AFMultipartFormData> formData))block
                  progress:(nullable void (^)(NSProgress * _Nonnull))uploadProgress
                   success:(void (^)(NSURLSessionDataTask *task, id responseObject))success
                   failure:(void (^)(NSURLSessionDataTask *task, NSError *error))failure

谢谢，

AFNetworking 2.0在故障块中从代码400获取JSON

4 个答案: