我正在尝试找出一个查询,该查询显示在1个以上部门工作的员工的数量(金额)。表名和字段在这里:
Employee
(id_employee,employee_name,salary)Department
(id_dept,dept_name,budget)Department_Employee
(id_employee,id_dept,workhours_percentage)假设Department_Employee表的内容为
id_employee id_dept workhours_percentage
----------- ------- --------------------
0001 03 100
0001 04 50
0001 05 60
0002 05 60
0002 09 90
0003 08 80
0004 07 80
0005 06 60
0006 05 70
0007 04 75
0008 10 95
0009 02 25
0010 01 40
使用正确的查询,结果应为2(员工),因为有2名员工在多个部门工作
我尝试了以下查询
SELECT COUNT(DISTINCT id_employee)
FROM Department_Employee
GROUP BY id_employee
HAVING COUNT(id_employee)>1
但结果不对。
请帮帮我。
感谢。
答案 0 :(得分:3)
让所有在多个部门工作的员工:
SELECT id_employee, COUNT(*)
FROM Department_Employee
GROUP BY id_employee
HAVING COUNT(*)>1
计算它们:
;
WITH cte As
(
SELECT id_employee
FROM Department_Employee
GROUP BY id_employee
HAVING COUNT(*)>1
)
SELECT COUNT(*) FROM cte
答案 1 :(得分:1)
SELECT COUNT(*)
FROM
(
SELECT id_employee, COUNT(*) AS CNT
FROM Department_Employee
GROUP BY id_employee
) AS T
WHERE CNT > 1
答案 2 :(得分:0)
select e.id_employee, count(e.id_dep) from Department_Employee e group by e.id_employee having count(e.id_dep)>1 ;
在此我尝试首先尝试通过id_employee获取dept id组的计数 并且我们的要求是使用count(e.id_dep)> 1来查找属于多个部门的员工以检索相同的人员。
答案 3 :(得分:0)
SELECT COUNT(*)
FROM (
SELECT id_employee, COUNT(*) AS CNT
FROM Department_Employee
GROUP BY id_employee
) AS T
WHERE CNT > 1