我正在为家庭作业创建一个MySQL数据库,并在phpmyadmin中遇到语法错误#1005。我认为它与外键有关,但如果w3schools有正确的话,我的语法应该是好的。
这是SQL语句;
create table if not exists customers
(
id int not null auto_increment,
cust_gname varchar(20) not null,
cust_fname varchar(30) not null,
cust_street varchar(30) not null,
cust_suburb varchar(30) not null,
cust_state varchar(6) not null,
cust_postcode varchar(4) not null,
cust_email varchar(50) not null,
cust_phone varchar(12),
cust_mobile varchar(12),
cust_user_id int,
foreign key (cust_user_id) references users(id),
primary key (id)
);
create table if not exists ingredients
(
id int,
name varchar(30) not null,
primary key (id)
);
create table if not exists recipes
(
id int,
name varchar(30) not null,
recipes_menu_id int,
foreign key (recipes_menu_id) references menus(id)
image varchar(30),
primary key (id)
);
create table if not exists ingredients_recipes
(
id int,
ingredients_recipes_ingredient_id int,
foreign key (ingredients_recipes_ingredient_id) references ingredients(id),
ingredients_recipes_recipe_id int,
foreign key (ingredients_recipes_recipe_id) references recipes(id),
primary key (id)
);
create table if not exists menus
(
id int,
description varchar(30) not null,
menus_restaurant_id int,
foreign key (menus_restaurant_id) references restaurants(id),
primary key (id)
);
create table if not exists restaurants
(
id int,
name varchar(30) not null,
address1 varchar(30) not null,
address 2 varchar(30),
suburb varchar(30) not null,
state varchar(10) not null,
postcode varchar(4) not null,
primary key (id)
);
create table if not exists customers_ingredients
(
id int,
customers_ingredients_customer_id int,
foreign key (customers_ingredients_customer_id) references customers(id),
customers_ingredients_ingredient_id int,
foreign key (customers_ingredients_ingredient_id) references ingredients(id),
primary key (id)
);
create table if not exists users
(
id int,
username varchar(40) not null,
password varchar(50) not null,
group_id int,
created DATETIME,
modified DATETIME,
primary key (id)
);
create table if not exists groups
(
id int,
name varchar(10) not null,
created DATETIME,
modified DATETIME,
primary key (id)
);
答案 0 :(得分:3)
如果要创建具有外键引用的表,则它所引用的表必须已存在。您正在脚本的开头创建一个customers
表,该表引用users
表,该表在结束之前不会创建。脚本中还有其他示例。
您需要以正确的顺序创建表格,或者使用顶部的set foreign_key_checks = 0;
来禁用此要求。创建完所有表后,请确保set foreign_key_checks = 1
结束。
注意:您的脚本中可能存在其他语法错误 - 我还没有检查过所有错误。