我在控制台应用程序中使用C#。
我需要从文本文件加载数据并将其加载到2d数组中。
这是我尝试过的,但当我尝试打印出返回内容时,没有任何内容被打印出来。
public static int[,] LoadMap()
{
const string path = @"1.txt";
string[] fileLines = File.ReadAllLines(path);
int[,] map = new int[fileLines.Length, 15];
string line;
for (int i = 0; i < fileLines.Length; ++i)
{
line = fileLines[i];
for (int j = 0; j < line.Length; ++j)
{
map[i, j] = (int)(line[j] - '0');
}
}
return map;
}
但是,当我对这些数据进行硬编码时,一切都会完美显示。
private static int[,] Map = new int[MapX, MapY]
{
{ 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1},
{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}
};
文本文件中的数据如下所示:
0,0,0,1,1,1,1,1,1,1,1,1,1,1,1
0,0,0,0,0,0,0,0,0,0,0,0,0,0,1
0,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,0,0,0,0,0,0,0,0,0,0,0,0,0,1
1,1,1,1,1,1,1,1,1,1,1,1,1,1,1
无论您是修复我尝试的内容还是提出完全不同的内容,都将不胜感激。谢谢。
答案 0 :(得分:3)
string[] fileLines = File.ReadAllLines(path);
int[,] map = new int[fileLines.Length,fileLines[0].Split(',').Length];
for (int i = 0; i < fileLines.Length; ++i)
{
string line = fileLines[i];
for (int j = 0; j < map.GetLength(1); ++j)
{
string[] split = line.Split(',');
map[i, j] = Convert.ToInt32(split[j]);
}
}
return map;
}
答案 1 :(得分:0)
您可以使用LINQ来解析这些行:
var lines = File.ReadAllLines(path);
int[,] map = new int[fileLines.Length, 25];
for (int i = 0; i < fileLines.Length; ++i)
{
var data = lines[i].Split(',').Select(c => Convert.ToInt32(c)).ToList();
for(int j =0; j<25; ++j)
map[i,j] = data[j];
}
return map;
如果你可以使用锯齿状数组而不是2D数组,这就变得更简单了:
public static int[][] LoadMap()
{
return File.ReadLines(path)
.Select(l => l.Split(',').Select(Convert.ToInt32).ToArray())
.ToArray();
}
答案 2 :(得分:0)
如果您的文本文件使用逗号分隔值,请替换此行:
for (int j = 0; j < line.Length; ++j)
使用:
for (int j = 0; j < line.Length; j += 2)
假设你的值总是只有1个字符。
答案 3 :(得分:0)
当数据来自文本文件时。如果用逗号分隔,可以使用string.split将其分隔。然后你加载你进入数组的内容并像平常一样访问它。 如下所示:
string[] lines = System.IO.File.ReadAllLines(@"path");
foreach (string line in lines)
{
string[] first= line.Split(comma);
}