通过带空格的字符串迭代

Question

我有一个字符串：results = "123 456 "

我想遍历字符串并打印：“1,2,3 ,, 4,5,6，”

到目前为止，这是我的代码：

results.each do |k|
  print k, ","
end

我也尝试过使用each_char。

Answer 1

这应该有效：

results.split('').join(',')
# => "1,2,3, ,4,5,6, "

Answer 2

results.each_char.map
# => ["1", "2", "3", " ", "4", "5", "6", " "]

或者，如果您想要一个字符串作为输出：

result.each_char.map.join(',')
# => "1,2,3, ,4,5,6, "

Answer 3

each_char适合我：

results = "123 456 "
results.each_char do |char|
  print "#{char},"
end

输出：

1,2,3, ,4,5,6, ,

Answer 4

"123 456 ".gsub(/(?<!\A)(?!\z)/, ",")
# => "1,2,3, ,4,5,6, "