不能在异常时显示UIAlert

时间:2013-10-25 13:17:04

标签: ios iphone objective-c uitableview exception-handling

我正在使用UITableView。如果没有网络连接,则viewDidload中会抛出异常。我的viewDidLoad函数是:

 @try {
                NSLog(@"Request URL = %@",URLString);

                NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL
                                                                  URLWithString:URLString]];
                NSData *response = [NSURLConnection sendSynchronousRequest:request
                                                     returningResponse:nil error:nil];

                NSError *jsonParsingError = nil;
                NSDictionary *tableData = [NSJSONSerialization JSONObjectWithData:response
                                                                      options:0
                                                                        error:&jsonParsingError];
                // Grab whole data with data field in JSON
                //    responseArray = [tableData objectForKey:@"data"];


                responseArray = [[NSMutableArray alloc]initWithArray:[tableData objectForKey:@"data"]];
                for(int i = 0; i < responseArray.count; i++)
                {
                    NSArray * tempArray = responseArray[i];
                    responseArray[i] = [tempArray mutableCopy];
                }


                UIButton *btn = [UIButton buttonWithType:UIButtonTypeCustom];
                [btn setFrame:CGRectMake(280.0, 0.0, 40.0, 40.0)];
                [btn setImage:[UIImage imageNamed:@"sort_icon.png"] forState:UIControlStateNormal];
                [btn addTarget:self action:@selector(showActionSheet) forControlEvents:UIControlEventTouchUpInside];
                UIBarButtonItem *barbutton = [[UIBarButtonItem alloc]initWithCustomView:btn];
                self.navigationItem.rightBarButtonItem = barbutton;

        }
        @catch (NSException *exception)
        {
            exceptionOccured = YES;
            NSLog(@"Exception Ocurred");
            UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Error in connectivity" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
            [alert show];
        }

在cellForRowAtIndexPath中我这样做:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    @try {

    NSMutableDictionary *tempDict = [[NSMutableDictionary alloc] init];
    tempDict = [responseArray objectAtIndex:indexPath.row];

    return cell;

    }
    @catch (NSException *exception)
    {
        NSLog(@"Error in CEll Create");
        NSLog(@"Draw Alert");
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Error in connectivity" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
        [alert show];
    }
}

在AlertViewDelegate函数中我正在做

- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{

    [self.navigationController popViewControllerAnimated:YES];
}

现在问题是,只要有异常并且重新抛出异常并显示错误

,它就不会显示警报
Thread 1: EXC_BAD_ACCESS(code=2, address=0x2)

任何帮助将不胜感激......

3 个答案:

答案 0 :(得分:1)

您应该避免在代码中抛出异常。

首先,您可以使用Reachability Class来确定是否有可用的互联网连接。

我明确建议使用NSURLConnectionDelegate协议进行网址连接。因此,您可以使用更好的异步编程风格。

答案 1 :(得分:0)

问题出在其他地方。调用- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath时,表示系统需要重新加载tableView。因此,您不应检查该函数内的数据。当您输入此功能时,您应确保您的数据正常。

您需要做的是首先检查特定功能中的数据:

     -(void)CheckData(NSArray *responseArray) {
            @try {
                //Retrieve your data & check if its valid
                self.dataArray = responseArray;
                [self.tableView reloadData];
            }
            @catch (NSException *exception)
            {
                NSLog(@"Error in check Data");
                NSLog(@"Draw Alert");
                UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Error     in connectivity" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
                [alert show];
            }

然后,实现您的数据源委托:

    -(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
           return [self.dataArray count];
       }

    -(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
        static NSString *CellIdentifier = @"Cell";

        UITableViewCell *cell = (UITableViewCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentifier];
        if(cell == nil){
            cell = [[[UITableViewCell alloc]initWithStyle:UITableViewStylePlain reuseIdentifier:CellIdentifier] autorelease] ; 
        }

        //TODO: Init your cell using your self.dataArray content

        return cell;
    } 

答案 2 :(得分:0)

我建议导入这个SystemConfiguration框架并使用相同的框架。这将检查网络连接是否可用。以下是简单的代码: -

    #import <SystemConfiguration/SystemConfiguration.h>
-(void)yourMethod
{    
     SCNetworkConnectionFlags flags = 0;
            if (yourhostname && [yourhostname length] > 0)
            {
                flags = 0;
                BOOL found = NO;
                SCNetworkReachabilityRef reachabilityRef = SCNetworkReachabilityCreateWithName(kCFAllocatorDefault, [yourhostname UTF8String]);
                if (reachabilityRef)
                {
                    found = SCNetworkReachabilityGetFlags(reachabilityRef, &flags)
                    &&  (flags & kSCNetworkFlagsReachable)
                    && !(flags & kSCNetworkFlagsConnectionRequired);
                    CFRelease(reachabilityRef);
                    reachabilityRef = NULL;
                }
                if (found)
                {       
                   NSLog(@"Connection available");         
                  }
                  else
                 {
                  NSLog(@"Connection not available");         
                  }
}