Question

我有以下字段的单个表格。

id    name          startdate                enddate
1     u1      2013-01-15 00:00:00.000   2013-01-17 00:00:00.000
2     u2    2013-01-22 00:00:00.000         2013-01-23 00:00:00.000
3     u3    2013-01-23 00:00:00.000         2013-01-23 00:00:00.000

现在，我希望多行取决于开始和结束日期。所以按照上面的行..它返回第一个记录的三行..日期15到17，返回3行（3天）。

我对查询感到有点困惑。有没有更好的方法或任何样本来实现？

感谢。

Answer 1

您可以使用CTE来解决这个问题：

DECLARE @Id int
SELECT  @Id = 1
;

WITH    Multiple AS
(
        SELECT  1 Sequence, Id, Name, StartDate, EndDate
        FROM    (       VALUES
                (1, 'u1', '2013-01-15', '2013-01-17'),
                (2, 'u2', '2013-01-22', '2013-01-23'),
                (3, 'u3', '2013-01-23', '2013-01-23')
        )       AS Sample(Id, Name, StartDate, EndDate)
        WHERE   Id = @Id
        UNION   ALL
        SELECT  Sequence + 1, Id, Name, StartDate, EndDate
        FROM    Multiple
        WHERE   Id = @Id AND DATEADD(d, Sequence, StartDate) <= EndDate
)
SELECT  *  
FROM    Multiple

Answer 2

如果您的“日期”表格中有“日期”列，请将您的表格加入“Dates.Date BETWEEN startdate AND enddate”上的“日期”。

Answer 3

我不太确定，但下面是我试过的......

SELECT c1.* 
FROM master..spt_values p 
    INNER JOIN tempQuery c1
        ON RIGHT(CAST(c1.stdate AS DATE),2) <= (CASE WHEN p.number = 0 THEN 1 ELSE p.number END)
WHERE TYPE='p'
AND p.number BETWEEN RIGHT(CAST(c1.stdate AS DATE),2) AND RIGHT(CAST(c1.endate AS DATE),2)

TSQL用于重复表中的行

3 个答案: