检索依赖于属性的数据

时间:2013-10-25 09:15:43

标签: sql sql-server

大家。我不能做以下查询。请帮忙。 初始数据和输出位于以下excel initial data/output google/drive

这是逻辑:对于'Rest'= 2500,它取最小值'Date',将其递增1并将其放入输出的Date1列; Date2收到下一个'Rest'值(1181,85)的日期的最小值..依此类推:Date1收到'Rest'(1181,85)'Date'(14.01.2013)的最小值加1( 15.01.2013)等等。它不应该对'Rest'值为零进行上述操作(它应该跳过它)。我们最初不能删除'Rest'值为零的行,因为他们的Date在Date2中使用,如上所述。有许多'accNumber',它应该列出所有这些。请帮忙。我希望你明白,如果不是要求更多细节。提前致谢。我正在使用SQL服务器。

1 个答案:

答案 0 :(得分:0)

如果我理解正确,您希望按休息编号对项目进行分组,然后显示最短日期+ 1天,以及“下一个”休息编号的最短日期。当Rest号码在两个不同的地方为0时,你期待发生什么?

with Base as
(
    select    t.AccNum,
              t.Rest,
              DATEADD(day, 1, MIN(t.Date)) as [StartDate],
              ROW_NUMBER() OVER (ORDER BY MIN(t.Date)) as RowNumber
    from      Accounts t
    where     t.Rest <> 0
    group by  t.AccNum, t.Rest
)
select      a.AccNum, a.Rest, a.StartDate, DATEADD(DAY, -1, b.StartDate) as [EndDate]
from        Base a
left join   Base b
on          a.RowNumber = b.RowNumber - 1
order by a.[StartDate]

如果Rest数字可能被进一步向下复制,但需要单独一个项目,那么我们在初始选择查询中需要更加聪明。

with Base as
(
    select  b.AccNum, b.Rest, MIN(DATEADD(day, 1, b.Date)) as [StartDate], ROW_NUMBER() OVER (ORDER BY MIN(Date)) as [RowNumber]
    from    (
        select  *, ROW_NUMBER() OVER (PARTITION BY Rest ORDER BY Date) - ROW_NUMBER() OVER (ORDER BY Date) as [Order]
        from    Accounts a
     -- where  a.Rest <> 0 
     -- If we're still filtering out Rest 0 uncomment the above line
    ) b
    group by [order], AccNum, Rest
)
select      a.RowNumber, a.AccNum, a.Rest, a.StartDate, DATEADD(DAY, -1, b.StartDate) as [EndDate]
from        Base a
left join   Base b
on          a.RowNumber = b.RowNumber - 1
order by a.[StartDate]

两个查询的结果:

Account Number          REST    Start Date  End Date
45817840200000057948    2500    2013-01-01  2013-01-14
45817840200000057948    1181    2013-01-15  2013-01-31
45817840200000057948    2431    2013-02-01  2013-02-09
45817840200000057948    1563    2013-02-10  NULL