我想知道如何使用不同数量的列对数据表进行rbindlist,并使用像rbind.fill这样的NA填充空行
DT1 <- data.table(A = 1:3)
DT2 <- data.table(A =4:5, B = letters[4:5])
l <- list(DT1, DT2)
rbindlist(l)
# Error in rbindlist(l) :
# Item 2 has 2 columns, inconsistent with item 1 which has 1 columns
我想要的是
A B
1: 1 NA
2: 2 NA
3: 3 NA
4: 4 d
5: 5 e
答案 0 :(得分:7)
o 'rbindlist' gains 'use.names' and 'fill' arguments and is now implemented
entirely in C. Closes #5249
-> use.names by default is FALSE for backwards compatibility (doesn't bind by
names by default)
-> rbind(...) now just calls rbindlist() internally, except that 'use.names'
is TRUE by default, for compatibility with base (and backwards compatibility).
-> fill by default is FALSE. If fill is TRUE, use.names has to be TRUE.
-> At least one item of the input list has to have non-null column names.
-> Duplicate columns are bound in the order of occurrence, like base.
-> Attributes that might exist in individual items would be lost in the bound result.
-> Columns are coerced to the highest SEXPTYPE, if they are different, if/when possible.
-> And incredibly fast ;).
-> Documentation updated in much detail. Closes DR #5158.
检查this post是否有基准。
1)使用fill
的{{1}}参数:
rbindlist
请注意,DT1 <- data.table(x=1, y=2)
DT2 <- data.table(y=2, z=-1)
rbindlist(list(DT1, DT2), fill=TRUE)
# x y z
# 1: 1 2 NA
# 2: NA 2 -1
时,fill=TRUE
应为use.names
。
2)适当地绑定具有重复名称的表:
TRUE
3)它不仅限于DT1 <- data.table(x=1, x=2, y=1, y=2)
DT2 <- data.table(y=3, y=-1, y=-2)
rbindlist(list(DT1, DT2), fill=TRUE)
# x x y y y
# 1: 1 2 1 2 NA
# 2: NA NA 3 -1 -2
,还适用于data.tables
和data.frames
:
lists
4)如果您只想按名称绑定,可以只设置DT1 <- data.table(x=1, y=2)
DT2 <- data.frame(y=2, z=-1)
DT3 <- list(z=10)
rbindlist(list(DT1,DT2,DT3), fill=TRUE)
# x y z
# 1: 1 2 NA
# 2: NA 2 -1
# 3: NA NA 10
,而不是use.names=TRUE
:
fill
5)默认情况与向后兼容性相同(DT1 <- data.table(x=1, y=2)
DT2 <- data.table(y=1, x=2)
rbindlist(list(DT1,DT2), use.names=TRUE, fill=FALSE)
# x y
# 1: 1 2
# 2: 2 1
DT1 <- data.table(x=1, y=2)
DT2 <- data.table(z=2, y=1)
# returns error when fill=FALSE but can't be bound without fill=TRUE
rbindlist(list(DT1, DT2), use.names=TRUE, fill=FALSE)
# Error in rbindlist(list(DT1, DT2), use.names = TRUE, fill = FALSE) :
# Answer requires 3 columns whereas one or more item(s) in the input
# list has only 2 columns. ...
,use.names=FALSE
):
fill=FALSE
HTH