Question

我的时间值如下 starttime like：09：00：00，结束时间如：10：00：00; 这里不需要日期值。所以这个值需要计算差值并转换成小时和分钟，秒。

我曾尝试过：

var test = new Date().getTime(startTime); 
var test1 = new Date().getTime(endTime);
var total = test1 - test;

有时我会得到NaN和1111111某种数字格式。

如何转换为HH：MM：SS，或任何其他寻找时差的方法。

Answer 1

您可以对时间值进行区分：

var diff = test1.getTime() - test.getTime(); // this is a time in milliseconds
var diff_as_date = new Date(diff);
diff_as_date.getHours(); // hours
diff_as_date.getMinutes(); // minutes
diff_as_date.getSeconds(); // seconds

Answer 2

var startTime = "09:00:00";
var endTime = "10:00:00";

var startDate = new Date("January 1, 1970 " + startTime);
var endDate = new Date("January 1, 1970 " + endTime);
var timeDiff = Math.abs(startDate - endDate);

var hh = Math.floor(timeDiff / 1000 / 60 / 60);
if(hh < 10) {
    hh = '0' + hh;
}
timeDiff -= hh * 1000 * 60 * 60;
var mm = Math.floor(timeDiff / 1000 / 60);
if(mm < 10) {
    mm = '0' + mm;
}
timeDiff -= mm * 1000 * 60;
var ss = Math.floor(timeDiff / 1000);
if(ss < 10) {
    ss = '0' + ss;
}

alert("Time Diff- " + hh + ":" + mm + ":" + ss);

Answer 3

function diff(start, end) {
start = start.split(":");
end = end.split(":");
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * 1000 * 60 * 60;
var minutes = Math.floor(diff / 1000 / 60);

// If using time pickers with 24 hours format, add the below line get exact hours
if (hours < 0)
   hours = hours + 24;

return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes;
}

时差并在javascript中转换为小时和分钟

3 个答案: