Jquery Ajax发布更新视图中的django会话

时间:2013-10-25 06:59:45

标签: jquery django-forms django-templates django-sessions

我从表单字段中发送值,以便将它们存储在django中的会话中。我正在执行以下操作,但它不会在django中接收POST中的数据。

<script type="text/javascript">

    var eventID = $('#id_eventID').val();
    var start = $('#id_start').val();
   $('a').click(function () {   
    console.log("Inside click");    
    $.post({
       url: "/update_session/",
       type: "POST",
       data: {eventID: eventID, start: start},
       success: function(response){},
       complete: function(){},
       error: function (xhr, textStatus, thrownError){
        alert("Error in ajax post");
       }
    });
    });
</script>

 <a href="Event/{{field.name}}"> Add signal</a>

我希望在点击上面的链接时执行此脚本,然后再打开一个新表单。所以,当我回到原始页面(填写表格后)时,我希望能够检索将存储在会话中的所有数据(按照我上面的方式)。

在我的 view.py 中,我有以下内容,

def update_session(request):
    print request.POST
    if request.is_ajax():
  try:
    request.session['eventID'] = request.POST['eventID']
    request.session['start'] = request.POST['start']
  except KeyError:
    return HttpResponse('Error')
    else:
  raise Http404

这样就没有在我的django termianl中打印出来。它显示一个空的Querydict {}。

另外,我实现所需功能的方法是否正确?还是有更好的方法来实现这一点......我是网络开发的新手.. 所以,一些来源或提示会很棒!

更新 * urls.py *

from django.conf.urls import patterns, url
from EiEventService import views

urlpatterns = patterns('',
   url(r'^$', views.event_view),
   url(r'^create/$', views.event_create),
   url(r'^eventSignals/$', views.eventSignal_create),
   url(r'^Intervals/$', views.interval_create),
   url(r'^eventBaseLine/$', views.EventBaseline_create),
   #url(r'^(?P<event_id>.*)/$', views.editEvent),
)

在视图中进行更改并添加由limelights提及的in urls.py。 我收到以下错误。整个追溯是,

Traceback (most recent call last):
File "/usr/lib/python2.7/wsgiref/handlers.py", line 86, in run
  self.finish_response()
File "/usr/lib/python2.7/wsgiref/handlers.py", line 127, in finish_response
  self.write(data)
File "/usr/lib/python2.7/wsgiref/handlers.py", line 210, in write
  self.send_headers()
File "/usr/lib/python2.7/wsgiref/handlers.py", line 268, in send_headers
  self.send_preamble()
File "/usr/lib/python2.7/wsgiref/handlers.py", line 192, in send_preamble
  'Date: %s\r\n' % format_date_time(time.time())
File "/usr/lib/python2.7/socket.py", line 324, in write
  self.flush()
File "/usr/lib/python2.7/socket.py", line 303, in flush
  self._sock.sendall(view[write_offset:write_offset+buffer_size])
error: [Errno 32] Broken pipe
----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 59495)
Traceback (most recent call last):
File "/usr/lib/python2.7/SocketServer.py", line 582, in process_request_thread
  self.finish_request(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 323, in finish_request
  self.RequestHandlerClass(request, client_address, self)
File "/usr/local/lib/python2.7/dist-packages/Django-1.5.1-py2.7.egg/django/core/servers/basehttp.py", line 150, in __init__
  super(WSGIRequestHandler, self).__init__(*args, **kwargs)
File "/usr/lib/python2.7/SocketServer.py", line 640, in __init__
  self.finish()
File "/usr/lib/python2.7/SocketServer.py", line 693, in finish
  self.wfile.flush()
File "/usr/lib/python2.7/socket.py", line 303, in flush
  self._sock.sendall(view[write_offset:write_offset+buffer_size])
error: [Errno 32] Broken pipe

1 个答案:

答案 0 :(得分:0)

您必须将/update_session/网址添加到您的urls.py中 - 这是您遇到的第一个也是最重要的问题。这也是您的脚本无法访问服务器的原因。

url(r'^/update_session/$', views.update_session)

这将成为网址模式。

此外,您还有一些其他问题会在您的开发中出现,所以我肯定会建议您阅读tutorial here