Question

我在jython中遇到这个随机java的问题。我在python中编写bukkit插件。这是代码：

class hween(PythonPlugin):
   def CandyChance(self):
       chance = self.cfg.getDouble("main.candydropchance", 50) / 100 #in config, it's 10, so I must do this to get it like 0.1...
       return chance

   @hook.event("block.BlockBreakEvent", "HIGHEST")        
   def onBlockBreakEvent(event):
       chance = pyplugin.CandyChance()
       print chance #When I print chance out, it's 0.1 (10 is in config) which is good I believe
       if(Random.nextDouble("%s"%chance)):
          #do something

Answer 1

这是一个交互式Jython会话，可以重现您的错误：

Jython 2.7b1 (default:ac42d59644e9, Feb 9 2013, 15:24:52)
[Java HotSpot(TM) 64-Bit Server VM (Oracle Corporation)] on java1.7.0_25
Type "help", "copyright", "credits" or "license" for more information.
>>> from java.util import Random
>>> Random.nextDouble("0.1")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: nextDouble(): self arg can't be coerced to java.util.Random
>>> Random.nextDouble()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: nextDouble(): expected 1 args; got 0
>>> Random().nextDouble()
0.3442604857098639
>>>

nextDouble()方法不是静态的，也不带任何参数。你将不得不重新思考如何使用“这个随机的java事物”（你不清楚你想要做什么）。

TypeError：nextDouble（）：self arg无法强制转换为java.util.Random

1 个答案: