为什么我的程序不打印指定输入的输出？
我有一个看起来像这样的网格：
我的程序所做的是它将计算是否获得徽章，如果徽章是否获得特定输入，它将打印出是或否（输入将是带有坐标的框） （x，y））。但出于某种原因，当我打印输出时，我的程序只计算黄色阴影区域。
在我的代码中，我通过说：
来说明不在边缘的方框if ((x >= 2 && x <= 19) && (y >= 2 && y <= 19))
但这似乎并没有解决我的问题。注意：如果输入（x，y）不在区间[1,20]中，那么我返回-1。
这是我打印结果时得到的结果：
如您所见，不在边缘的字段中的银色徽章的输出不会显示。我似乎无法弄清楚为什么不在边缘的盒子没有被计算/打印出来。
注意：当一个字段获得两个或更多青铜徽章时，Poly徽章会返回“是”。
注意：任意颜色徽章会在以下情况下返回徽章：
-
如果所有邻近的田地都没有青铜徽章（邻近地区包括西北，东北，西南和东南），一块土地可以获得0枚青铜徽章
-
一个领域获得1枚青铜徽章，其总体得分（声称为fieldScore）为20或以上。
-
一个领域获得2枚青铜徽章，并且至少有以下一种情况：该字段不会获得任何利润（声明为fieldProfit），收获时间不到80天（声明为harvestTime），或者它的阳光暴露（声称为sunExposure）大于其灌溉暴露（宣称为灌溉暴露）。
-
如果至少有两个直接邻居获得两枚或更多枚铜徽章，则可以获得3枚或以上的青铜徽章。 （直接邻居是北，南，东，西）。
这是我的两个银徽章功能代码（Poly徽章和任意颜色徽章）：
int countBadges(int x, int y) {
int mavebadge, incirclebadge, herobadge, weatherbadge, inquattrobadge,
total;
mavebadge = badgeBoundaryMaven(x, y);
incirclebadge = badgeInnerCircle(x, y);
herobadge = badgeLocalHero(x, y);
weatherbadge = badgeBoringWeather(x, y);
inquattrobadge = badgeInQuattro(x, y);
total = mavebadge + incirclebadge + herobadge + weatherbadge +
inquattrobadge;
return total;
printf("Total number: %d\n", countBadges(2, 2));
}
int badgePoly(int x, int y) {
int bronzebadges, polybadge;
if ((x >= 1 && x <= 20) && (y >= 1 && y <= 20)) {
bronzebadges = countBadges(x, y);
if (bronzebadges >= 2) {
polybadge = 1;
}
else {
polybadge = 0;
}
}
else {
polybadge = -1;
}
return polybadge;
}
int badgeAnyColor(int x, int y) {
int bronzebadges, northbadges, northeastbadges, northwestbadges, eastbadges,
westbadges, southbadges, southeastbadges, southwestbadges, colorbadge;
double fs, ht, fp, sunexp, irrexp;
if ((x >= 1 && x <= 20) && (y >= 1 && y <= 20)) {
fs = fieldScore(x, y);
ht = harvestTime(x, y);
fp = fieldProfit(x, y);
sunexp = sunExposure(x, y);
irrexp = irrigationExposure(x, y);
bronzebadges = countBadges(x, y);
northbadges = countBadges(x, y + 1);
northeastbadges = countBadges(x + 1, y + 1);
northwestbadges = countBadges(x - 1, y + 1);
eastbadges = countBadges(x + 1, y);
westbadges = countBadges(x - 1, y);
southbadges = countBadges(x - 1, y - 1);
southeastbadges = countBadges(x + 1, y - 1);
southwestbadges = countBadges(x - 1, y - 1);
switch (bronzebadges) {
case 0: {
if (x == 1 && y == 1){
if (northbadges == 0 && northeastbadges == 0 &&
eastbadges == 0){
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if (x == 20 && y == 1) {
if (northbadges == 0 && northwestbadges == 0 &&
westbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if (x == 1 && y == 20) {
if (eastbadges == 0 && southeastbadges == 0 &&
southbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if (x == 20 && y == 20) {
if (westbadges == 0 && southwestbadges == 0 &&
southbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x >= 2 && x <= 19) && (y == 1)) {
if (westbadges == 0 && northwestbadges == 0 && northbadges == 0
&& northeastbadges == 0 && eastbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x >= 2 && x <= 19) && (y == 20)) {
if (westbadges == 0 && southwestbadges == 0 && southbadges == 0
&& southeastbadges == 0 && eastbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x == 20) && (y >= 2 && y <= 19)) {
if (northbadges == 0 && northwestbadges == 0 &&
westbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x == 1) && (y >= 2 && y <= 19)) {
if (northbadges == 0 && northeastbadges == 0 && eastbadges == 0
&& southeastbadges == 0 && southbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x >= 2 && x <= 19) && (y >= 2 && y <= 19)) {
if (northbadges == 0 && northwestbadges == 0 && westbadges == 0
&& southwestbadges == 0 && southbadges == 0 &&
southeastbadges == 0 && eastbadges == 0 &&
northeastbadges == 0) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
break;
}
case 1: {
if (fs >= 20) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
break;
}
case 2: {
if (fp <= 0 || ht < 80 || sunexp > irrexp) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
break;
}
case 3:
case 4:
case 5: {
if ((x >= 2 && x <= 19) && y == 1) {
if (((westbadges + northbadges) >= 2) || ((northbadges +
eastbadges) >= 2) || ((westbadges + eastbadges) >= 2)) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if (x == 1 && y == 1) {
if ((northbadges + eastbadges) >= 2) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if (x == 20 && y == 1) {
if ((northbadges + westbadges) >= 2) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if (x == 1 && y == 20) {
if ((southbadges + eastbadges) >= 2) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if (x == 20 && y == 20) {
if ((southbadges + westbadges) >= 2) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x >= 2 && x <= 19) && y == 20) {
if (((westbadges + southbadges) >= 2) || ((southbadges +
eastbadges) >= 2) || ((westbadges + eastbadges) >= 2)) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x == 1) && (y >= 2 && y <= 19)) {
if (((northbadges + eastbadges) >= 2) || ((eastbadges +
southbadges) >= 2) || ((northbadges + southbadges) >= 2)) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x == 20) && (y >= 2 && y <= 19)) {
if (((northbadges + westbadges) >= 2) || ((westbadges +
southbadges) >= 2) || ((northbadges + southbadges) >= 2)) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
if ((x >= 2 && x <= 19) && (y >= 2 && y <= 19)) {
if (((northbadges + westbadges) >= 2) || ((westbadges +
southbadges) >= 2) || ((southbadges + eastbadges) >= 2) ||
((northbadges + southbadges) >= 2) || ((westbadges +
eastbadges) >= 2)) {
colorbadge = 1;
}
else {
colorbadge = 0;
}
}
break;
}
}
}
else {
colorbadge = -1;
}
return colorbadge;
}
1 个答案:
答案 0 :(得分：1)
您的countBadges（x，y）函数在printf之前有一个return语句，因此printf永远不会打印。您应将其移至返回上方，并在不需要时将其注释掉。你可能还有printf的其他问题。
int countBadges(int x, int y)
{
int mavebadge, incirclebadge, herobadge, weatherbadge, inquattrobadge,
total;
mavebadge = badgeBoundaryMaven(x, y);
incirclebadge = badgeInnerCircle(x, y);
herobadge = badgeLocalHero(x, y);
weatherbadge = badgeBoringWeather(x, y);
inquattrobadge = badgeInQuattro(x, y);
total = mavebadge + incirclebadge + herobadge + weatherbadge +
inquattrobadge;
printf("Total number: %d\n", countBadges(2, 2));
return total;
}
你经常检查你的网格位置，所以我会建议一个函数（或宏），ongrid（x，y），并用它来检查有效的网格边界位置，
int ongrid(x,y)
{
return ( (x>=1) && (x<=20) && (y>=1) && (y<=20) );
}
您还应检查边界条件，
if( y + 1<=20 )
northbadges = countBadges(x, y + 1);
if( x + 1<=20 && y + 1<=20 )
northeastbadges = countBadges(x + 1, y + 1);
if( x - 1>=1 && y + 1<=20 )
northwestbadges = countBadges(x - 1, y + 1);
if( x + 1<=20 )
eastbadges = countBadges(x + 1, y);
if( x - 1<=20 )
westbadges = countBadges(x - 1, y);
if( y - 1>=1 )
southbadges = countBadges(x, y - 1); //this value was probably not right
if( x + 1<=20 && y - 1>=1 )
southeastbadges = countBadges(x + 1, y - 1);
if( x - 1>=1 && y - 1>=1 )
southwestbadges = countBadges(x - 1, y - 1);
使用ongrid（）函数重写以获得更清晰，
if( ongrid(x,y + 1) )
northbadges = countBadges(x, y + 1);
if( ongrid(x + 1,y + 1) )
northeastbadges = countBadges(x + 1, y + 1);
if( ongrid(x - 1,y + 1) )
northwestbadges = countBadges(x - 1, y + 1);
if( ongrid(x + 1,y) )
eastbadges = countBadges(x + 1, y);
if( ongrid(x - 1,y) )
westbadges = countBadges(x - 1, y);
if( ongrid(x,y - 1) )
southbadges = countBadges(x, y - 1);
if( ongrid(x + 1,y - 1) )
southeastbadges = countBadges(x + 1, y - 1);
if( ongrid(x - 1,y - 1) )
southwestbadges = countBadges(x - 1, y - 1);
青铜徽章的switch语句没有默认值;如果您的徽章数量明确不同，则需要处理默认值
default : {
break;
}
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