使用TextView期望String返回Int

时间:2013-10-24 17:29:51

标签: java android textview listitem viewgroup

我是android开发和stackoverflow的新手,所以请放轻松我。 ;)

我创建了一个包含许多TextView的ViewGroup。一个特别是有一个switch case,其中case常量是我的java对象中定义的整数。然后我将case语句设置为我认为是String值。最后,我使用setText()方法将TextView对象设置为此String。我遇到的问题是实际返回到视图的是与大小写关联的整数而不是文本值。这让我相信我传递给TextView的是一个int,但我不知道如何或在哪里可以纠正这个。

非常感谢任何帮助。

ViewGroup代码在这里:

public View getView (int position, View convertView, ViewGroup parent)
    {
        ViewGroup listItem;
        if (convertView == null) {
            listItem = (ViewGroup) getLayoutInflator().inflate(R.layout.list_item, null);
        }
        else {
            listItem = (ViewGroup) convertView;
        }
        MovieInfo movieInfo = list.get(position);
        TextView movietitleText = (TextView) listItem.findViewById(R.id.movietitle_text);
        TextView directorText = (TextView) listItem.findViewById(R.id.director_text);
        TextView producerText = (TextView) listItem.findViewById(R.id.producer_text);
        TextView releaseyearText = (TextView) listItem.findViewById(R.id.releaseyear_text);
        TextView genreText = (TextView) listItem.findViewById(R.id.genre_text);

        movietitleText.setText(movieInfo.getMovietitle());
        producerText.setText(movieInfo.getProducer());
        directorText.setText(movieInfo.getDirector());
        releaseyearText.setText(movieInfo.getReleaseyear());

        String genreName;
        Resources resources = context.getResources();
        switch (movieInfo.getGenre()) {
        case MovieInfo.GENRE_ACTION:
            genreName = resources.getString(R.string.action_label);
            break;
        case MovieInfo.GENRE_COMEDY:
            genreName = resources.getString(R.string.comedy_label);
            break;
        case MovieInfo.GENRE_DRAMA:
            genreName = resources.getString(R.string.drama_label);
            break;
        case MovieInfo.GENRE_FAMILY:
            genreName = resources.getString(R.string.family_label);
            break;
        case MovieInfo.GENRE_HORROR:
            genreName = resources.getString(R.string.horror_label);
            break;
        case MovieInfo.GENRE_ROMANCE:
            genreName = resources.getString(R.string.romance_label);
            break;
        default:
        case MovieInfo.GENRE_UNKNOWN:
            genreName = resources.getString(R.string.unknown_label);
            break;
        }
        genreText.setText(genreName);
        return listItem;
    }

大小写常量在我的java对象中定义:

public static final int GENRE_UNKNOWN  = 0;
public static final int GENRE_ACTION   = 1;
public static final int GENRE_COMEDY   = 2;
public static final int GENRE_DRAMA    = 3;
public static final int GENRE_FAMILY   = 4;
public static final int GENRE_HORROR   = 5;
public static final int GENRE_ROMANCE  = 6;

private String movietitle;
private String director;
private String producer;
private String releaseyear;
private int genre;

选中复选框时设置流派的操作在此处的主要活动中:

if (actionCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_ACTION);
if (comedyCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_COMEDY);
if (dramaCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_DRAMA);
if (familyCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_FAMILY);
if (horrorCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_HORROR);
if (romanceCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_ROMANCE);

Strings.xml的部分在这里:

<string name="movietitle_label">Movie Title</string> 
<string name="director_label">Director</string> 
<string name="producer_label">Producer</string> 
<string name="releaseyear_label">Release Year</string> 
<string name="genre_label">Genre</string> 
<string name="action_label">Action</string> 
<string name="comedy_label">Comedy</string> 
<string name="drama_label">Drama</string> 
<string name="family_label">Family</string> 
<string name="horror_label">Horror</string> 
<string name="romance_label">Romance</string> 
<string name="unknown_label">Unknown</string> 
<string name="ok_label">OK</string> 
<string name="clear_label">Clear</string> 
<string name="showdatabase_label">Show Database</string> 
<string name="id_label">ID</string> 
<string name="select">Select Year</string> 

感谢您的帮助!

1 个答案:

答案 0 :(得分:0)

我认为您的代码没有任何问题。这里有几件事要尝试(也许你只需要重新编译并重新运行它?):

尝试使用资源ID而不是字符串(即R.string.unknown_label等)调用setText:https://developer.android.com/reference/android/widget/TextView.html#setText%28int%29

尝试在调用setText之前记录genreName的值:

Log.d("MovieGenre", "genreName=" + genreName);