Question

我有一个值为“3D7H40M20S”的字符串哪个应该转换为3天7小时40分钟和20秒“。这是我到目前为止所尝试的：

        BindingContainer bindings = BindingContext.getCurrent().getCurrentBindingsEntry();
    AttributeBinding attr = (AttributeBinding)bindings.getControlBinding("ScreeningSLAWaitTimeDuration");
    scrSlaWaitDur = (String)attr.getInputValue();
    System.out.println("-------------------------------------------SCREENING SLA WAIT DURATION---------------"+scrSlaWaitDur);
    scrSlaWaitDur = scrSlaWaitDur.substring(2, scrSlaWaitDur.length());
    System.out.println("--------------------------------------------SUBSTRING--------------------"+scrSlaWaitDur);
    int dIndex = scrSlaWaitDur.indexOf("D");
    System.out.println("*******************************************INDEX OF D**********************************"+dIndex);
    if(dIndex != -1){
        String newDur = scrSlaWaitDur.substring(0, dIndex)+" days "+scrSlaWaitDur.substring(dIndex+1);
        int mIndex = scrSlaWaitDur.lastIndexOf("M");
        String newDur2 = scrSlaWaitDur.substring(0, mIndex)+" minute "+scrSlaWaitDur.substring(mIndex+1);
        int sIndex = newDur2.lastIndexOf("S");
        String newDur3 = newDur2.substring(0,sIndex)+" second";
        scrSlaWaitDur = newDur3;
        return scrSlaWaitDur;
    }

我知道这很烦人且非常冗长。我能以更简单的方式达到要求吗？

Answer 1

务实的方法是取代单位代币：

return scrSlaWaitDur.replace("D", " Days ").replace("H", " Hours ").replace("M", " Minutes ").replace("S", " Seconds");

输出：

3 Days 7 Hours 40 Minutes 20 Seconds

Answer 2

您可以使用不带index（）的substring（），即：

String result = 
scrSlaWaitDur.replace("D"," Days ").replace("H"," Hours ").replace("M"," Minutes ").replace("S"," Seconds");

但我相信有人会想出一个fency正则表达式解决方案。 ; - ）

如何设置持续时间字符串？

2 个答案: