Question

msvc-11.0中的std :: thread实现似乎忽略了调用约定。

我有以下程序：

的main.cpp

 # include <stdio.h>
 # include <thread>

 class foo
 {
 public:
    //intentional __stdcall, breaks compilation
    virtual void __stdcall printOut(const char* str)
    {
       printf("%s", str);
    }
 };

 foo bar;

 int main(void)
 {
    std::thread(&foo::printOut, &bar, "Printing output");
    return 0;
 }

尝试使用msvc 11.0（VS2012）编译上述代码会引发以下错误：

error C2064: term does not evaluate to a function taking 2 arguments
        ...\functional(1152) : while compiling class template member function 'std::_Do_call_ret<_Forced,_Ret,_Funx,_Btuple,_Ftuple>::type std::_Bind<false,_Ret,_Fun,_V0_t,_V1_t,_V2_t,_V3_t,_V4_t,_V5_t,<unnamed-symbol>>::operator ()(void)'
        with
        [
            _Forced=false,
            _Ret=void,
            _Funx=void (__stdcall foo::* )(const char *),
            _Btuple=std::tuple<foo *,const char *>,
            _Ftuple=std::tuple<>,
            _Fun=void (__stdcall foo::* )(const char *),
            _V0_t=foo *,
            _V1_t=const char (&)[13],
            _V2_t=std::_Nil,
            _V3_t=std::_Nil,
            _V4_t=std::_Nil,
            _V5_t=std::_Nil,
            <unnamed-symbol>=std::_Nil
        ]
        .../xthread(195) : see reference to function template instantiation 'std::_Do_call_ret<_Forced,_Ret,_Funx,_Btuple,_Ftuple>::type std::_Bind<false,_Ret,_Fun,_V0_t,_V1_t,_V2_t,_V3_t,_V4_t,_V5_t,<unnamed-symbol>>::operator ()(void)' being compiled
        with
        [
            _Forced=false,
            _Ret=void,
            _Funx=void (__stdcall foo::* )(const char *),
            _Btuple=std::tuple<foo *,const char *>,
            _Ftuple=std::tuple<>,
            _Fun=void (__stdcall foo::* )(const char *),
            _V0_t=foo *,
            _V1_t=const char (&)[13],
            _V2_t=std::_Nil,
            _V3_t=std::_Nil,
            _V4_t=std::_Nil,
            _V5_t=std::_Nil,
            <unnamed-symbol>=std::_Nil
        ]
       ...\thread(52) : see reference to class template instantiation 'std::_Bind<_Forced,_Ret,_Fun,_V0_t,_V1_t,_V2_t,_V3_t,_V4_t,_V5_t,<unnamed-symbol>>' being compiled
        with
        [
            _Forced=false,
            _Ret=void,
            _Fun=void (__stdcall foo::* )(const char *),
            _V0_t=foo *,
            _V1_t=const char (&)[13],
            _V2_t=std::_Nil,
            _V3_t=std::_Nil,
            _V4_t=std::_Nil,
            _V5_t=std::_Nil,
            <unnamed-symbol>=std::_Nil
        ]
        main.cpp(24) : see reference to function template instantiation 'std::thread::thread<void(__stdcall foo::* )(const char *),foo*,const char(&)[13]>(_Fn,_V0_t &&,_V1_t)' being compiled
        with
        [
            _Fn=void (__stdcall foo::* )(const char *),
            _V0_t=foo *,
            _V1_t=const char (&)[13]
        ]

没有__stdcall，这个程序构建正常。拥有或没有调用约定IMO应该对std :: thread无关紧要，但它似乎影响了这个方法的解释方式。编译器似乎很难看到printOut(const char*)符合定义 - (foo::* )(const char *)。

这是msvc 11.0的问题还是我错过了什么？

std :: thread-ing __stdcall方法

的main.cpp

0 个答案: