我正在使用此安装脚本将一个py文件编译为exe。
# -*- coding: utf-8 -*-
from distutils.core import setup
import py2exe
import sys
import os
dataFiles = []
sampleDir = r'.\\lang'
for root, dirs, files in os.walk(sampleDir):
sampleList = []
if files:
for filename in files:
#ignore SVN dirs
if ".svn" not in root:
sampleList.append(os.path.join(root, filename))
if sampleList:
dataFiles.append((root, sampleList))
class Target:
def __init__(self, **kw):
self.__dict__.update(kw)
self.version = "1.5.5.000"
self.company_name = "company"
self.copyright = 'Copyright (c) '
target = Target(
script = "script.py",
icon_resources=[(1, 'ico.ico')],
)
setup(
name = 'PROGNAME',
author='me',
author_email='me@me.com',
description = 'desc',
windows = [target],
options = {
'py2exe': {
'packages': 'encodings, kinterbasdb',
'includes': 'cairo, pango, pangocairo, atk, gobject, gio, glib, gtk',
}
},
data_files=dataFiles,
)
但现在我有两个py文件,我想立即编译它,但每个文件应该有:
如何更改我的设置脚本以便能够立即执行此操作?
答案 0 :(得分:1)
我发现了怎么做!希望这对每个人都有帮助:
# -*- coding: utf-8 -*-
from distutils.core import setup
import py2exe
import sys
import os
dataFiles = []
sampleDir = r'.\\lang'
for root, dirs, files in os.walk(sampleDir):
sampleList = []
if files:
for filename in files:
#ignore SVN dirs
if ".svn" not in root:
sampleList.append(os.path.join(root, filename))
if sampleList:
dataFiles.append((root, sampleList))
class Target:
def __init__(self, **kw):
self.__dict__.update(kw)
target = Target(
script = "script.py",
icon_resources=[(1, 'ico.ico')],
version = "1.5.5.000",
company_name = "company",
copyright = 'Copyright (c) ',
name = 'PROGNAME',
)
target2 = Target(
script = "script2.py",
icon_resources=[(1, 'ico.ico')],
version = "1.0.0.000",
company_name = "company",
copyright = 'Copyright (c) ',
name = 'SECOND PROGNAME',
)
setup(
author='me',
author_email='me@me.com',
description = 'desc',
windows = [target, target2],
options = {
'py2exe': {
'packages': 'encodings, kinterbasdb',
'includes': 'cairo, pango, pangocairo, atk, gobject, gio, glib, gtk',
}
},
data_files=dataFiles,
)