SELECT id, country FROM my_records
我从MySQL查询得到了上述结果,我想从结果中删除重复的ID。 不是在PHP代码的帮助下,而是使用MySQL查询。是否有任何功能或查询来做同样的事情。
由于
答案 0 :(得分:7)
我陷入了类似的情况,发现MySql没有提供任何预定义的功能来克服这个问题。
为了克服我创建了一个UDF,请看下面的定义和用法。
DROP FUNCTION IF EXISTS `get_unique_items`;
DELIMITER //
CREATE FUNCTION `get_unique_items`(str varchar(1000)) RETURNS varchar(1000) CHARSET utf8
BEGIN
SET @String = str;
SET @Occurrences = LENGTH(@String) - LENGTH(REPLACE(@String, ',', ''));
SET @ret='';
myloop: WHILE (@Occurrences > 0)
DO
SET @myValue = SUBSTRING_INDEX(@String, ',', 1);
IF (TRIM(@myValue) != '') THEN
IF((LENGTH(@ret) - LENGTH(REPLACE(@ret, @myValue, '')))=0) THEN
SELECT CONCAT(@ret,@myValue,',') INTO @ret;
END if;
END IF;
SET @Occurrences = LENGTH(@String) - LENGTH(REPLACE(@String, ',', ''));
IF (@occurrences = 0) THEN
LEAVE myloop;
END IF;
SET @String = SUBSTRING(@String,LENGTH(SUBSTRING_INDEX(@String, ',', 1))+2);
END WHILE;
SET @ret=concat(substring(@ret,1,length(@ret)-1), '');
return @ret;
END //
DELIMITER ;
样本用法:
SELECT get_unique_items('2,2,2,22,2,3,3,3,34,34,,54,5,45,,65,6,5,,67,6,,34,34,2,3,23,2,32,,3,2,,323') AS 'Items';
结果:
2,22,3,34,54,45,65,67,23,32,323
希望这有帮助!
答案 1 :(得分:1)
这可能会对您有所帮助。
DELIMITER //
DROP FUNCTION IF EXISTS `find_duplicate_using_comma` //
CREATE FUNCTION `find_duplicate_using_comma` (in_str LONGTEXT) RETURNS LONGTEXT
DETERMINISTIC
NO SQL
BEGIN
DECLARE out_str LONGTEXT DEFAULT NULL; -- pending output
DECLARE next_str TEXT DEFAULT NULL; -- next element under consideration
dedup:
LOOP
IF CHAR_LENGTH(TRIM(in_str)) = 0 OR in_str IS NULL THEN
LEAVE dedup; -- no more data to consider
END IF;
SET next_str = SUBSTRING_INDEX(in_str,',',1); -- find the next element
SET in_str = SUBSTRING(in_str FROM (CHAR_LENGTH(next_str) + 1 + 1)); -- remove that element
SET in_str = TRIM(in_str), next_str = TRIM(next_str); -- trim the new and the rest
IF FIND_IN_SET(next_str,out_str) OR CHAR_LENGTH(next_str) = 0 THEN -- if empty or already found
ITERATE dedup;
END IF;
SET out_str = CONCAT_WS(',',out_str,next_str); -- append the new to pending output
END LOOP;
RETURN out_str;
END //
DELIMITER ;
示例:
SELECT find_duplicate_using_comma('6675,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661,8661') AS data;
Result : 6675,8661
答案 2 :(得分:0)
给出的其他解决方案不区分大小写,如果您希望结果区分大小写并且不删除诸如'o'和'ö'之类的带重音的匹配项,并寻找精确且严格的匹配项,则此代码为
如果utf8mb4_bin不起作用,请尝试utf8_bin或其他二进制类型。
DELIMITER //
DROP FUNCTION IF EXISTS `find_duplicate_using_comma` //
CREATE FUNCTION `find_duplicate_using_comma` (in_str LONGTEXT) RETURNS LONGTEXT
DETERMINISTIC
NO SQL
BEGIN
DECLARE out_str LONGTEXT DEFAULT NULL; -- pending output
DECLARE next_str TEXT DEFAULT NULL; -- next element under consideration
dedup:
LOOP
IF CHAR_LENGTH(TRIM(in_str)) = 0 OR in_str IS NULL THEN
LEAVE dedup; -- no more data to consider
END IF;
SET next_str = SUBSTRING_INDEX(in_str,',',1); -- find the next element
SET in_str = SUBSTRING(in_str FROM (CHAR_LENGTH(next_str) + 1 + 1)); -- remove that element
SET in_str = TRIM(in_str), next_str = TRIM(next_str); -- trim the new and the rest
IF FIND_IN_SET(next_str collate utf8mb4_bin,out_str collate utf8mb4_bin) OR CHAR_LENGTH(next_str) = 0 THEN -- if empty or already found
ITERATE dedup;
END IF;
SET out_str = CONCAT_WS(',',out_str,next_str); -- append the new to pending output
END LOOP;
RETURN out_str;
END //
DELIMITER ;