这个代码应该工作正常,据我所知,但由于某种原因它不起作用。有人能帮帮我吗?!! T_T
js script:
$.ajax({
type: 'POST',
url: '<?=base_url()?>/folder_name_ajax/unit_vacancy',
dataType: 'json',
data:{unit_id:unit_id, unit_landlord_id:unit_landlord_id, unit_stat:unit_stat},
beforeSend: function(){
},
success: function(response){
console.log(response);
alert('Unit status successfully updated.');
}
});
控制器:
function unit_vacancy()
{
$this->load->model('modelAjax');
$unit_id = mysql_real_escape_string($this->input->post('unit_id'));
$unit_landlord_id = mysql_real_escape_string($this->input->post('unit_landlord_id'));
$unit_stat = mysql_real_escape_string($this->input->post('unit_stat'));
$xplod_stat = explode('-',$unit_stat);
$this->modelAjax->update_unit_vacancy();
}
型号:
function update_unit_vacancy()
{
$unit_id = mysql_real_escape_string($this->input->post('unit_id'));
$unit_landlord_id = mysql_real_escape_string($this->input->post('unit_landlord_id'));
$unit_stat = mysql_real_escape_string($this->input->post('unit_stat'));
$xplod_stat = explode('-',$unit_stat);
$result = $this->db->query("SELECT COUNT(ID) AS count FROM ".TBL_PREFIX."".UNIT_VACANT_TBL." WHERE unit_id = '$unit_id' ");
$count = $result->num_rows();
if($count == 0)
{
$result = $this->db->query("INSERT INTO ".TBL_PREFIX."".UNIT_VACANT_TBL."
(
unit_id,
landlord_id,
status
)
VALUES
(
'$unit_id',
'$unit_landlord_id',
'insert'
)
");
}
else
{
$result = $this->db->query("UPDATE ".TBL_PREFIX."".UNIT_VACANT_TBL."
SET
status = 'update'
WHERE
unit_id = '$unit_id'
");
}
}
我似乎无法理解我在这里做错了什么!!!
答案 0 :(得分:1)
我看到你的控制器中没有echo(ing)
任何东西。你的json
在哪里?您的update_unit_vacancy()
返回json
吗?如果yes
然后echo
它。
echo $this->modelAjax->update_unit_vacancy();
并检查您的控制台是否有ajax的响应。不过会再向你推荐一件事,改变下面一行:
url: '<?=base_url()?>index.php/rentdaddy_ajax/unit_vacancy',