仅将选定的复选框添加到数据库-PHP

Question

我有以下表格：

    <form action="done.php" method="POST">
<!-- This hidden check box is used to check if submit is clicked.-->
 <input type="hidden" name="check_submit" value="1" />
 <!--All the applications are added to an array which we can then use in done.php-->
<applications><h2>Applications</h2><br><table border="0" cellspacing="10" cellpadding="10">
<tr>
    <td><b>Application</b></td>
    <td><b>UK</b></td>
    <td><b>Spain</b></td>
    <td><b>France</b></td>
    <td><b>Benelux</b></td>
    <td><b>Germany</b></td>
    <td><b>Sweeden</b></td>
</tr>
<tr>
    <td>hey</td>
    <td><center><input type = "checkbox" name="hey[]" value ="heyuk"/></center></td>
        <td><center><input type = "checkbox" name="hey[]" value ="heyspain"/></center></td>
            <td><center><input type = "checkbox" name="hey[]" value ="heyfrance"/></center></td>
                <td><center><input type = "checkbox" name="hey[]" value ="heybenelux"/></center></td>
                    <td><center><input type = "checkbox" name="hey[]" value ="heygermany"/></center></td>
                        <td><center><input type = "checkbox" name="hey[]" value ="heysweeden"/></center></td>
</tr>

  

<input type="submit" value="Update">

</submitb>

</form>

然后我的done.php会在发布时收到数据。

   <?php

 // First we execute our common code to connection to the database and start the session 
    require("common.php"); 


 //Check whether the form has been submitted
if (array_key_exists('check_submit', $_POST)) {
   //Converts the new line characters (\n) in the text area into HTML line breaks (the <br /> tag)
   if ( isset($_POST['hey']) ) { 
     $print = implode(', ', $_POST['hey']); //Converts an array into a single string
   echo $print;
    echo('<br>');
   }

所以这一切都完美无缺。但是，我有一个名为hey的数据库，如下所示：

接下来我要发生的是，如果为该应用程序选择了一个国家/地区，它会在相关字段中为数据库添加1。

我不确定如何继续这个，因为我无法保证目前阵列中每个元素的位置是什么。请你就此提出建议吗？谢谢。

Answer 1

我有同样的问题，我去解决它如下，我使用PDO插入数据库......

<td><center><input type = "checkbox" name="hey[0][UK]" value ="UK"/></center></td>
<td><center><input type = "checkbox" name="hey[0][SPAIN]" value ="SPAIN"/></center></td>
<td><center><input type = "checkbox" name="hey[0][FRANCE]" value ="FRANCE"/></center></td>
<td><center><input type = "checkbox" name="hey[0][BENELUX]" value ="BENELUX"/></center></td>
<td><center><input type = "checkbox" name="hey[0][GERMANY]" value ="GERMANY"/></center></td>
<td><center><input type = "checkbox" name="hey[0][SWEEDEN]" value ="SWEEDEN"/></center></td>

然后在您的查询中执行以下操作...

 $arr = $_POST["hey"];
        try {

            // depend on your server setting, you might need this to put it on.
           // $glb_connection->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );

            //Loop through all row-value from the forms 
            foreach($arr as $key=>$value){

               if(count(array_filter($value)) >0){

               $data = array( 'UK' => $value['UK'], 'SPAIN' => $value['SPAIN'], 'FRANCE' => $value['FRANCE'], 'BENELUX' => $value['BENELUX'], 'GERMANY' => $value['GERMANY'], 'SWEEDEN' => $value['SWEEDEN'] );  
              $query = $glb_conn->prepare("INSERT INTO HEY (UK, SPAIN, FRANCE, BENELUX, GERMANY, SWEEDEN) VALUES (:UK, :SPAIN, :FRANCE, :BENELUX, :GERMANY, :SWEEDEN)");                           

               $query->bindValue(':UK', $value['UK']);
               $query->bindValue(':SPAIN', $value['SPAIN']);
               $query->bindValue(':FRANCE', $value['FRANCE']);  
               $query->bindValue(':BENELUX', $value['BENELUX']);                                      
               $query->bindValue(':GERMANY', $value['GERMANY']);                        
               $query->bindValue(':SWEEDEN', $value['SWEEDEN']);                        
               $query->execute($data); 
                }
            }

        } //end try
        catch(PDOException $e) {
            echo $e->getMessage();
        }

这应该像魅力一样，我已经测试了它。

Answer 2

只需将国家/地区名称指定为复选框的值即可。当您发布此类表单时，作为值，您将获得仅选定国家/地区的数组（复选框），因此稍后您将只需更新适当的列。 所以你的表单checkobxes输入应该声明为

<td><center><input type = "checkbox" name="hey[]" value ="SPAIN"/></center></td>

为西班牙等。

$updateClause = ""; // this is the part betwean `SET` and `WHERE` ofc.
foreach($country as $hey){ // hey would be an array of selected country names.
    $updateClause.="$country = $country+1" // dont forget to add `,` or you will get SQL syntax error.
}

应该很容易实现。