首先要做的事情
使用:
我在现有数据库上映射了多对多的关系。 我的模型看起来像这样:
class EventMap < ActiveRecord::Base
self.table_name="TAKE_PART"
self.primary_key="id"
belongs_to :event, foreign_key: "lottery_event_id"
belongs_to :entrant, foreign_key: "address_id"
end
class Event < ActiveRecord::Base
self.table_name="THE_EVENT"
self.primary_key="id"
has_many :event_maps
has_many :entrants, :through => :event_maps
end
class Entrant < ActiveRecord::Base
self.table_name="ADDRESSES"
self.primary_key="id"
self.set_date_columns :date_of_birth
has_many :event_maps
has_many :events, :through => :event_maps
end
当我尝试获取事件的所有地址时:
def show
@entrants = Event.find(params[:id]).entrants
end
我这样得到一个Oracle错误:
OCIError: ORA-00904: "TAKE_PART"."ENTRANT_ID": SELECT "THE_EVENT".* FROM "THE_EVENT" INNER JOIN "TAKE_PART" ON "THE_EVENT"."ID" = "TAKE_PART"."LOTTERY_EVENT_ID" WHERE "TAKE_PART"."ENTRANT_ID" = :a1
这里的问题似乎是TAKE_PART的外键没有正确使用,它应该是 address_id ,而是使用型号名称 entrant_id
这是oracle中增强的错误还是我在表的匹配方面做错了什么?
答案 0 :(得分:1)
您的课程的关联未完全定义,但是Event
和Entrant
都不知道正确的ID,他们应该转到EventMap
。正确的方法如下:
class EventMap < ActiveRecord::Base
...
belongs_to :event, :foreign_key => "lottery_event_id"
belongs_to :entrant, :foreign_key => "address_id"
end
class Event < ActiveRecord::Base
...
has_many :event_maps, :foreign_key => "lottery_event_id"
has_many :entrants, :through => :event_maps
end
class Entrant < ActiveRecord::Base
...
has_many :event_maps, :foreign_key => "address_id"
has_many :events, :through => :event_maps
end
它有效,因为event.entrants
意味着对数据库执行以下操作(简化):
加入两个表
EventMap
和Entrant
,以便address_id&lt; =&gt; entrant.id (映射1)
在连接表中,使用lottery_event_id = event.id (映射2)找到所有字符串
映射1 :
has_many :entrants, :through => :event_maps #Join two tables
belongs_to :entrant, :foreign_key => "address_id" #matching address_id with entrants.id
#belongs_to+foreign_key tells to EventMap which key to use for referring to Event object
映射2 :
has_many :event_maps, :foreign_key => "lottery_event_id" #associate event.id with lottery_event_id
#has_many+foreign_key tells to Event which key EventMap uses for referring to Event object
或者以更正式的方式:
SELECT "entrants".* FROM "entrants" INNER JOIN "event_maps" ON "entrants"."id" =
"event_maps"."address_id" WHERE "event_maps"."lottery_event_id" = ? [["lottery_event_id", 1]]