我将使用C#中的OleDbDataAdapter在Access数据库中插入数据,但是我收到错误消息 INSERT INTO命令中的语法错误
BackgroundWorker worker = new BackgroundWorker();
OleDbDataAdapter dbAdapter new OleDbDataAdapter();
OleDbConnection dbConnection = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=E:\\PMS.mdb");
worker = new BackgroundWorker();
worker.WorkerReportsProgress = true;
worker.DoWork += InsertJob;
worker.ProgressChanged += InsertJobCompleted;
worker.RunWorkerAsync(args);
InsertJob函数是:
private void InsertJob(object sender, DoWorkEventArgs e)
{
var args = (InsertJobArgs)e.Argument;
try
{
dbAdapter.SelectCommand = new OleDbCommand("SELECT * FROM Sheet", dbConnection);
dbAdapter.Fill(args.DataTable);
var builder = new OleDbCommandBuilder(dbAdapter);
var row = args.DataTable.NewRow();
row["UserName"] = args.Entry.UserName;
row["Password"] = args.Entry.Password;
args.DataTable.Rows.Add(row);
dbAdapter.InsertCommand = builder.GetInsertCommand();
dbAdapter.Update(args.DataTable);
builder.Dispose();
}
catch (Exception ex)
{
args.Exception = ex;
worker.ReportProgress(0, args);
return;
}
worker.ReportProgress(100, args);
}
我在线收到错误:dbAdapter.Update(args.DataTable);
我尝试使用visual studio调试它,发现所有InsertCommand参数值都是null
我尝试在调用dbAdapter.Update(args.DataTable);
dbAdapter.InsertCommand.Parameters[0].Value = args.Entry.UserName;
dbAdapter.InsertCommand.Parameters[1].Value = args.Entry.Password;
答案 0 :(得分:14)
试试这个:
紧接在
之后var builder = new OleDbCommandBuilder(dbAdapter);
添加两行
builder.QuotePrefix = "[";
builder.QuoteSuffix = "]";
这将告诉OleDbCommandBuilder
将表名和列名包装在方括号中,产生一个INSERT命令,如
INSERT INTO [TableName] ...
而不是默认表单
INSERT INTO TableName ...
如果任何表或列名称包含空格或“有趣”字符,或者它们恰好是Access SQL中的保留字,则需要使用方括号。 (在您的情况下,我怀疑您的表有一个名为[Password]的列,而PASSWORD
是Access SQL中的保留字。)