Question

/*This assignment is to create 2 parallel arrays – jobs& salaries
*Read file from “careers.txt” into arrays
*one line – job
*next line –salary
*Sort Salaries {from highest}
*then swap jobs if salary swapped
*Display output of careers and salaries from the highest on a formatted table.
* 
 */
package assignment7;
import java.util.*;//importing Scanner


public class Coordinator 
{


    public static void main(String[] args) throws Exception
    {// the main method creates the arrays and calls on each method to perform 
        //its work.
     String [] job = new String[20];//creating a string array having 20 spaces
     int[] salary = new int[20];//creating an integer array having 20 spaces
     int count;// number of spaces actually occupied in the array

     **count = readFile(job, salary);**// calling a method to read text into both
                                   //arrays and return the number of spaces 
                                   //occupied in the array

     sorter(job,salary,count);// calling on method to arrange file from highest
     //to lowest

     display(job, salary,count);// calling on method present the output


    }
    public static int readFile(String[] jobber, int[] salaro) throws Exception
    { // this method reads a text file and copies into arrays and also
        //returns the number of spaces occupied in the array
            int n = 0; //keeps track of number of times a line is fed into an 
            //array

            //set up a file class object linked up to the name of the file to 
            //be read
            java.io.File unread = new java.io.File("career.txt");

            // create a scanner instance to read the input from the file
            Scanner infile = new Scanner(unread);

            /*This while loop reads line of text into the arrays, it uses 
             * boolean
             * function hasNextLine() and the created scanner instance.
             */
            while (infile.hasNextLine() || infile.hasNextInt())
            {
                jobber[n] = infile.nextLine();
                **salaro[n] = infile.nextInt()**;
                n++;
            }//end while
            infile.close();//close scanner class
            return n;// return number of spaces filled

    }//end of readFile method


    public static void sorter(String[] jobestic, int[] salawe, int z) 
            throws Exception
    {// this method sorts the array from the highest paid job to the lowest.

      boolean swapped;// keeps track of when a swap takes place
      int i;// variable fo for loop
      int temp;// helps in swap
      String temp2;// helps in swap

      do
      {
          swapped = false;
          for (i= 0; i < z-1; i++)// a pass through the array
          {
              if (salawe[i+1] > salawe[i])
              // if the number before it is less they swap
              {
                  //swap starts
                  temp = salawe[i+1];
                  salawe[i+1] = salawe[i];
                  salawe[i] = temp;
                  //swaps the jobs too if the salary is swapped
                  temp2 = jobestic[i+1];
                  jobestic[i+1] = jobestic[i];
                  jobestic[i] = temp2;

                  swapped = true;
              }// end if


          }// end for

      } while (swapped);
   }// end sorter method

   public static void display(String[] jobo, int[] salary5 ,int k) throws Exception
   {

       //this method displays the output as a formatted table
       int i;
       System.out.printf("%-60s%15s%n", "Job", "Salary");





       for(i=0; i<k; i++)



           System.out.printf("%-60s%,15d%n", jobo[i], salary5[i]);

   }








}

请大家，这段代码有什么问题？我一遍又一遍地绞尽脑汁，无法弄清楚出了什么问题......我运行了这段代码，但我一直在犯错......错误总是表明粗线。我试图读取的文本文件如下。我想将作业标题存储在一个数组中，并将相应的工资存储在另一个数组中。像并行数组一样。请问代码有什么问题？我想将工资存储为整数，因为我在提供输出时将其格式化为整数。谢谢。

Computer and Information Research Scientists
102190
Computer and Information Analysts
80460
Computer Systems Analysts
79680
Information Security Analysts
86170
Software Developers and Programmers
87100
Computer Programmers
74280
Software Developers(Applications)
90060
Software Developers(Systems Software)
99000
Web Developers
62500
Database and Systems Administrators and Network Architects
76880
Database Administrators
77080
Network and Computer Systems Administrators
72560
Computer Network Architects
91000
Computer Support Specialists
48900
Computer User Support Specialists
46420
Computer Network Support Specialists
59090

错误：

Exception in thread "main" java.util.InputMismatchException 
at java.util.Scanner.throwFor(Scanner.java:909) 
at java.util.Scanner.next(Scanner.java:1530) 
at java.util.Scanner.nextInt(Scanner.java:2160) 
at java.util.Scanner.nextInt(Scanner.java:2119) 
at assignment7.Coordinator.readFile(Coordinator.java:56)
at assignment7.Coordinator.main(Coordinator.java:25)

Answer 1

这个问题或其等价物似乎每隔几天就被问到一次。

当您拨打nextInt()时，您的扫描仪会在号码后停止。然后，当您之后立即致电nextLine()时，您实际上正在读取该行号末尾的新行字符。你不是在读下一行。因此，在循环的下一次迭代中，当您在扫描仪旁边排列非数字文本时，您将调用nextInt()。

每次拨打nextLine()后，都会额外拨打nextInt()，只是为了阅读额外的换行符。

从java中的文本文件中读取字符串和整数

1 个答案: