Question

我正在尝试做线性函数，但我能做的唯一一个是（0,0）..我想要包含输入但我需要修复这个..我怎么能绘制（3,4）for例。此外，我将通过二次函数和极地改进这一点，所以如果你能给我一些提示或主题，我可以搜索帮助我。

这里我得到了什么

import numpy as np
import matplotlib.pyplot as plt

fig = plt.figure()
x = np.linspace(-np.pi,np.pi,100)
y = 2*np.sin(x)

ax = fig.add_subplot(1,1,1)
ax.set_title('Zero Function')
ax.plot(x,y)
ax.spines['left'].set_position('zero')
ax.spines['right'].set_color('none')
ax.spines['bottom'].set_position('zero')
ax.spines['top'].set_color('none')
ax.spines['left'].set_smart_bounds(True)
ax.spines['bottom'].set_smart_bounds(True)
ax.xaxis.set_ticks_position('bottom')
ax.yaxis.set_ticks_position('left')


def adjust_spines(ax,spines):
    for loc, spine in ax.spines.items():
        if loc in spines:
            spine.set_position(('outward',10)) # outward by 10 points
            spine.set_smart_bounds(True)
        else:
            spine.set_color('none') # don't draw spine

    # turn off ticks where there is no spine
    if 'left' in spines:
        ax.yaxis.set_ticks_position('left')
    else:
        # no yaxis ticks
        ax.yaxis.set_ticks([])

    if 'bottom' in spines:
        ax.xaxis.set_ticks_position('bottom')
    else:
        # no xaxis ticks
        ax.xaxis.set_ticks([])



plt.show()

我如何管理信息？

0 个答案: