Question

如何使我的lblAnzeige颜色为红色，白色，绿色，黄色和蓝色？（所以当我点击btnGelb时，文本lblAnzeige会改变其中五种颜色之一的颜色）在我的代码中，它改变了一种rgb颜色，但没有改变为正确的5种颜色：（

private void btnGelb_Click(object sender, EventArgs e)
{
    int summe = 0, z;
    lblAnzeige.Text = " ";
    while (summe <= 0)
    {
        z = r.Next(1, 6);
        summe = summe + z;
    }
    lblAnzeige.Text += colors[summe - 1] + "\n";
    lblAnzeige.ForeColor = Color.FromArgb(Farbe.Next(256), Farbe.Next(256), Farbe.Next(256));
}

Answer 1

您可以将颜色存储在列表或数组中，然后从列表中随机选择一个。

static readonly IList<Color> myColors =
        new[] { Color.Red, Color.Blue, Color.Green, Color.White, Color.Yellow };
private void btnGelb_Click(object sender, EventArgs e)
{
    int summe = 0, z;
    lblAnzeige.Text = " ";
    while (summe <= 0)
    {
        z = r.Next(1, 6);
        summe = summe + z;
    }
    lblAnzeige.Text += colors[summe - 1] + "\n";
    lblAnzeige.ForeColor = myColors[Farbe.Next(myColors.Count)];
}

Answer 2

    Private Function RandomColor() As System.Drawing.Color
        Dim MyAlpha As Integer
        Dim MyRed As Integer
        Dim MyGreen As Integer
        Dim MyBlue As Integer
        Randomize()
        MyAlpha = CInt(Int((254 * Rnd()) + 0))
        Randomize()
        MyRed = CInt(Int((254 * Rnd()) + 0))
        Randomize()
        MyGreen = CInt(Int((254 * Rnd()) + 0))
        Randomize()
        MyBlue = CInt(Int((254 * Rnd()) + 0))
        Return Color.FromArgb(MyAlpha, MyRed, MyGreen, MyBlue)

    End Function

我已经在一个vb项目中拥有它...我不应该很难将它转换为C＃

虽然我更喜欢其他答案，但这可能会以更加迂回的方式发挥作用

    private void Random()
    {
        RandomNumber random = new RandomNumber();
        int randomInt = random.RandomInRange(1, 5);
    if (randomInt == 1)
            {
                lblLabel.ForeColor =  System.Drawing.Color.Red;
            }
            else if (randomInt == 2)
            {
                lblLabel.ForeColor =  System.Drawing.Color.Yellow;
            }
    else if(randomInt ==3)
            {
        lblLabel.ForeColor =  System.Drawing.Color.White;
            }
            else if (randomInt == 4)
            {
                lblLabel.ForeColor =  System.Drawing.Color.Blue;
            }
            else if (randomInt == 5)
            {
                lblLabel.ForeColor =  System.Drawing.Color.Green;
            }
    }


class RandomNumber
{
    public int RandomInRange(int l, int u)
    {
        Random generator = new Random();
        return generator.Next(l, u);
    }
}

Answer 3

使用这种简单的字体颜色技术，可以进一步扩展..

    Random NewRGBColor = new Random();
    LastIssueTxtBox.ForeColor = Color.FromArgb(NewRGBColor.Next(256), NewRGBColor.Next(256), NewRGBColor.Next(256));

斯蒂芬

随机颜色文字

3 个答案: