Mysql 5.5 / phpmyadmin简单查询之谜

Question

如果我在我的PhpMyAdmin（版本4.0.5）上运行此select - 查询：

(SELECT *
FROM prenotazione
WHERE stato = 'prenotato'
AND (to_days( data ) +2) < to_days( NOW( ) )
)

运行良好。

但是，如果我运行delete - 查询不起作用：

(DELETE *
FROM prenotazione
WHERE stato = 'prenotato'
AND (to_days( data ) +2) < to_days( NOW( ) )
)

有人请解释一下，为什么会这样。

Answer 1

只是

DELETE FROM ...

不是

DELETE * FROM ...
      ^^^

有关详细信息，请参阅DELETE Syntax

Answer 2

进行如下查询：

(DELETE FROM prenotazione WHERE stato = 'prenotato' AND (to_days( data ) +2) < to_days( NOW( ) ) )

有关详细信息，请检查删除语法manual

Answer 3

这项工作在查询之前和之后没有*和括号

DELETE
FROM prenotazione
WHERE stato = 'prenotato'
AND (to_days( data ) +2) < to_days( NOW( ) )